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3 years ago

The shape of the data is

Mathematics

2 answers:

mihalych1998 [28]3 years ago

6 0

Answer:

B) skewed right

Step-by-step explanation:

If you draw a bell curve on this data, you'll observe a tail towards right side.

Hence positively/right skewed

Tcecarenko [31]3 years ago

5 0

Skewed right

With right-skewed distribution (also known as "positively skewed" distribution), most data falls to the right, or positive side, of the graph's peak. Thus, the histogram skews in such a way that its right side (or "tail") is longer than its left side.

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8,000 of 2ounces how many make 16 ounces

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1,000 I guess I don't really understand the question
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3 years ago

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25 POINTS

uysha [10]

Answer:

a reflection over the x-axis and then a 90 degree clockwise rotation about the origin

Step-by-step explanation:

Lets suppose triangle JKL has the vertices on the points as follows:

J: (-1,0)

K: (0,0)

L: (0,1)

This gives us a triangle in the second quadrant with the 90 degrees corner on the origin. It says that this is then transformed by performing a 90 degree clockwise rotation about the origin and then a reflection over the y-axis. If we rotate it 90 degrees clockwise we end up with:

J: (0,1) , K: (0,0), L: (1,0)

Then we reflect it across the y-axis and get:

J: (0,1), K:(0,0), L: (-1,0)

Now we go through each answer and look for the one that ends up in the second quadrant;

If we do a reflection over the y-axis and then a 90 degree clockwise rotation about the origin we end up in the fourth quadrant.

If we do a reflection over the x-axis and then a 90 degree counterclockwise rotation about the origin we also end up in the fourth quadrant.

If we do a reflection over the x-axis and then a reflection over the y-axis we also end up in the fourth quadrant.

The third answer is the only one that yields a transformation which leads back to the original position.

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3 years ago

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Find the equation of the line that passes through (2,8) and (6,48)

kolezko [41]

Answer: m = 10

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3 years ago

The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$

d) $t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)$

$N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h$

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3 years ago

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olasank [31]

Answer:

Srry Cant read it :(

Step-by-step explanation:

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3 years ago