Answer: 55.5 (A.)
Step-by-step explanation:
Since angle A = 29 and angle B = 41, angle C must be equal to 110
180 = m<A + m<B + m<C
180 = 29 +41 + m<C
180 = 70 + m<C
110 = m<C
Therefore, side c must be the longest, side b must be the second longest, and side a must be the shortest.
Since side length a, angle A, and angle B are known, one can use the law of sines to solve for side b.
Law of Sines: sinA/a = sinB/b = sinC/c
sinA/a = sinB/b
sin29/41 = sin41/b
b(sin29/41) = sin41
b = 41(sin41)/(sin29)
b = 55.48
b = 55.5
C) sss similarity
because each side as a partner with half of its value
8in-4in
6in-3in
4in-2in
Hello I hope this helps. I'm pretty sure this is the answer.
Part A: C
Part B: A
Answer:
DE = 13.4 cm (to 1 decimal place)
Step-by-step explanation:
Given: ABCD is a square
BC = AC = 12 cm (opposite sides of a square are congruent)
E is midpoint of BC (given)
BE = EC = 12/2 = 6 cm
CD = AB = 12 cm (opposite sides of a square are congruent)
angle ECD is a right angle (interior angles of a square are 90 deg.)
Consider right triangle ECD
DE = sqrt(EC^2+CD^2) ............. pythagorean theorem
= sqrt(6^2+12^2)
= sqrt ( 36+144 )
= sqrt (180)
= 2 sqrt(45)
= 13.416 (to three dec. places)
