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3 years ago

M + 9 = -12 what do you do first

Mathematics

2 answers:

Taya2010 [7]3 years ago

7 0

Answer:

You subtract 9 from both sides

Step-by-step explanation:

You have to get the variable by itself to solve so you subract 9 by 9 and they cancel each other out. Then you do -12-9 and since they are both negative you get get -21

Them you have your answer m=-21, you can check this by plugging m inot the equation

jeyben [28]3 years ago

4 0

If you are solving for M

You would subtract 9

m + 9 = -12

- 9 - 9

M = -21

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3 years ago

A casino features a game in which a weighted coin is tossed several times. The table shows the probability of each payout amount

kkurt [141]

Answer:

The expected payout of the game is $230.46.

Step-by-step explanation:

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3 years ago

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Vinvika [58]

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Step-by-step explanation:

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2 years ago

Use matrices and elementary row to solve the following system:

LiRa [457]

I assume the first equation is supposed to be

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$5x-3x+2x=4x=13$

As an augmented matrix, this system is given by

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]$

Multiply through row 3 by 1/2:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]$

Add -1(row 2) to row 3:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]$

Multiply through row 3 by 1/5:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]$

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

$\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Add -3(row 2) to row 1:

$\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Multiply through row 1 by -1:

$\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Add -2(row 1) to row 2:

$\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]$

Multipy through row 2 by -1:

$\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]$

The solution to the system is then

$\boxed{x=1,y=-2,z=1}$

5 0

3 years ago