Fill in the square with <, >, or = to make a true statement = 12 or 4.3

Alex runs on the track at school each weekday morning. If he runs 5.9 miles each day, about how much does he run every month?

Lisa [10]

Now, since we know that 5.9 is the amount of miles per day, we need to determine how many miles per month.

Usually, there are 20 days...because of no weekdays

Multiply.

5.9 * 20 = 118

Final answer:- He runs 118 miles per month.

3 0

3 years ago

Read 2 more answers

3 less than m is greater than 9

Artist 52 [7]

Answer:

m-9 = 3 is the required expression

5 0

3 years ago

Read 2 more answers

marys age is 2 upon 3 that of peters age. two years ago marys age was 1 upon 2 of whats peters age will be in 5years time. how o

Nitella [24]

Answer:

the Peter age be 27

Step-by-step explanation:

Let assume peter be

And, then mary is 2p ÷ 3

So

The equation would be

2p ÷ 3 - 2 = 1 ÷ 2 (p + 5)

4p - 12 = 3p + 15

p = 27

So Peter age be 27

And, the mary age is

= 2 (27) ÷ 3

= 18

Hence, the Peter age be 27

4 0

2 years ago

A train from Portland, Oregon, to Los Angeles, California, travels at an average speed of 60 miles per hour and covers a distanc

seropon [69]

Answer:

The train need to leave Portland at 03:27 am

Step-by-step explanation:

step 1

Find out how long it takes the train to travel from Portland, Oregon, to Los Angeles, California

Remember that

The speed is equal to divide the distance by the time

so

The time is equal to divide the distance by the speed

Let

s ---> the speed in miles per hour

d ---> the distance in miles

t ---> the time in hours

$t=\frac{d}{s}$

we have

$d=963\ mi$

$s=60\ mi/h$

substitute

$t=\frac{963}{60}=16.05\ hours$

step 2

Adds 30 minutes (time it takes to get from the train station to her aunt's house)

Remember that

$30\ minutes=0.50\ hours$

$16.05+0.50=16.55\ hours$

Convert to minutes

$16.55\ h=16.55(60)\ min=993\ min$

step 3

Remember that

$8 p.m=20:00\ hrs$

Convert to minutes

$20(60)=1,200\ min$

Subtract 993 minutes from 1,200 minutes

$1,200-993=207\ min$

Convert to hours+minutes

$207\ min=207/60=3.45\ hours$

$0.45\ h=0.45(60)=27\ min$

so

$3\ h+27\ min$

$00:00 + 03:27=03:27\ am$

therefore

The train need to leave Portland at 03:27 am

8 0

3 years ago

Please help! Simplify. Your answer should contain only positive exponents.

maxonik [38]

Answer:

$\frac{1}{4k^3}$

Step-by-step explanation:

It's already in a form that only ha positive exponents. Just to state it though you could rewrite it as $k*(4k^{4})^{-1}$ or $k*4^{-1}*k^{-4}$ The question asks for positive exponents though so yu don't need to do that.

You also need to know $\frac{x^a}{x^b}=x^{a-b}$ so in this case $\frac{k}{k^4}=\frac{k^1}{k^4} =k^{1-4}=k^{-3}=\frac{1}{k^3}$

so $\frac{k}{4k^4}=\frac{1}{4}*\frac{k}{k^4}=\frac{1}{4}*\frac{1}{k^3}=\frac{1}{4k^3}$

3 0

3 years ago