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Scilla [17]
3 years ago
11

A casino features a game in which a weighted coin is tossed several times. The table shows the probability of each payout amount

(assume that the remaining probability has a payout of 0 so that the probabilities add to 1). To the nearest dollar what is expected payout of the game? $4400 $145000 $160 Payout Amount 0.0007 0.024 Probability 0.146 Download C$v Copy to Clipboard Help Provide your answer below: SUBMIT MORE INSTRUCTION FEEDBACK Content attribution Previous
Mathematics
1 answer:
kkurt [141]3 years ago
6 0

Answer:

The expected payout of the game is $230.46.

Step-by-step explanation:

The given table is

Payout Amount :    $160       $4400      $145000      

Probability         :    0.146       0.024          0.0007

We need to find the expected payout of the game.

The formula for expected payout is

\text{Expected payout}=\sum n_iP(x_i)

where, n is amount and P(x) is probability of that event. The value of n is negative for loss.

Using the above formula we get

\text{Expected payout}=160\times 0.146+4400\times 0.024+145000\times 0.0007

\text{Expected payout}=23.36+105.6+101.5

\text{Expected payout}=230.46

Therefore the expected payout of the game is $230.46.

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