(701+y)/(3+1)<200
(701+y)/4<200
701+y<800
y<99
So the most yards they can allow in the next game is 98 yards
We know that
points are
x intercept
A (4,0)
y intercept
B (0,11)
step 1
find the equation of a line
m=(y2-y1)/(x2-x1)--------> m=(11-0)/(0-4)------> m=-11/4
with m and the point B (0,11)
y-y1=m*(x-x1)y-11=(-11/4)*(x-0)---------> y=-(11/4)x+11
the answer is
the formula of the function is y=-(11/4)x+11
see the attached figure
Answer:
Step-by-step explanation:
hello : here is a solution
Answer:
y=x+1/2z+-1/2
Step-by-step explanation:
Let's solve for y.
2x−2y+z=1
Step 1: Add -2x to both sides.
2x−2y+z+−2x=1+−2x
−2y+z=−2x+1
Step 2: Add -z to both sides.
−2y+z+−z=−2x+1+−z
−2y=−2x−z+1
Step 3: Divide both sides by -2.
-2y/-2 = -2-z+1/-2
y=x +1/2z+-1/2
Answer:
x = 15
Therefore, the length and width are 31 and 47.
Step-by-step explanation:
Perimeter = (2x + 1) + (2x + 1) + (3x + 2) + (3x + 2) = 156
Simplified,
10x + 6 = 156
Subtract 6 from both sides, then divide by 10.
10x = 150
x = 15
To find the length and width, substitute 15 (the value of x) into the individual equations.
2(15) + 1 = 31
3(15) + 2 = 47