The air within a piston equipped with a cylinder absorbs 565 J of heat and expands from an initial volume of 0.10 L to a final v
1 answer:
Answer:
489 J
Explanation:
According to the first law of thermodynamics:-
Where,
U is the internal energy
q is the heat
w is the work done
From the question,
q = + 565 J (+ sign as the heat is being absorbed)
The expression for the calculation of work done is shown below as:
Where, P is the pressure
is the change in volume
From the question,
= 0.85 - 0.10 L = 0.75 L
P = 1.0 atm
Also, 1 atmL = 101.3 J
So,
(work is done by the system)
So,
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Answer:
a) -1.325 μC
b) 4.17μC
Explanation:
First, you need to know that charge is conserved. So, the adition of the charges, as there is no lost in charge, should always be the same. Also, after the wire is removed, both spheres will have the same charge, trying to find equilibrium. In summary:
We know both q1f and q2f must be positive, because the negative charge at the beginning was the the smaller.
The electrostatic force is equal to:
K is the Coulomb constant, equal to 9*10^9 Nm^2/C^2
Now, we are told that the electrostatic force after the wire is equal to 0.0443 N:
Originally, the force is negative because it was an attraction force, therefore, its direction was opposite to the direction of the repulsive force after the wire:
Solving the quadratic equation:
for this values q_1 wil be:
So as you can see, the negative charge will always be -1.325 μC and the positive 4.17μC