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yarga [219]
3 years ago
14

Find the equation of the line that passes through the points 2,5 and -8,4

Mathematics
1 answer:
n200080 [17]3 years ago
4 0

Answer:

y = 1/10 x  + 24/5

or in standard form this is

-x + 10y = 48.

Step-by-step explanation:

The slope of the line is (5-4)/(2--8)

= 1/10

Using the point slope form y - y1 = m(x - x1):

USING THE POINT (2, 5):

y - 5 = 1/10(x - 2)

y - 5 = 1/10 x - 1/5

y = 1/10 x  + 24/5

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19m=2 and g=3, what is 3(m+3g)-(2m)
Vikki [24]
The answer is 27.1052631579 or 27.1 if you rounded "m" to .10
5 0
3 years ago
What is the measure of angle x?
RSB [31]

Answer:

128 degrees! (veritcal angles)

4 0
3 years ago
Find the value of x.<br> (8x - 11)<br> 5x°<br> (2x+6)°
ira [324]

Answer: x=37/3

Step-by-step explanation:

8x-11+5x+2x+6=180 ==> three angles of a triangle add up to 180 degrees

8x+5x+2x-11+6=180

13x+2x-5=180

15x-5=180

15x=185

x=185/15

x=37/3

5 0
1 year ago
How would I solve this problem?
Nataliya [291]

The area of the garden enclosed by the fencing is

A(x, y) = xy

and is constrained by its perimeter,

P = x + 2y = 200

Solve for x in the constraint equation:

x = 200 - 2y

Substitute this into the area function to get a function of one variable:

A(200 - 2y, y) = A(y) = 200y - 2y²

Differentiate A with respect to y :

dA/dy = 200 - 4y

Find the critical points of A :

200 - 4y = 0   ⇒   4y = 200   ⇒   y = 50

Compute the second derivative of A:

d²A/dy² = -4 < 0

Since the second derivative is always negative, the critical point is a local maximum.

If y = 50, then x = 200 - 2•50 = 100. So the farmer can maximize the garden area by building a (100 ft) × (50 ft) fence.

3 0
2 years ago
Nay at I wants to swim 50 miles this school year.she plans to swim 1/4 of a mile each day.How many days will it take her to swim
Hoochie [10]
Hey there!

Multiply 50 and 4 and you would get 200

It would take 200 days for Nay to swim 50 miles

Hope this helps!
6 0
3 years ago
Read 2 more answers
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