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3 years ago

3 (3n-4)=3 (n+4) help help

1 answer:

5 0

(3n-4)=3(n+4)
3n-4=3n+12
no solution

There wouldn’t be a solution to this equation because the n cancels out when you subtract 3n-3n.

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4x + y< 2

bulgar [2K]

The two inequalities can be rewritten as

$\begin{cases}y-2\end{cases}$

The solution is composed by every point below the graph of the line $y=-4x+2$ , and above the horizontal line $y=-2$

To draw the line $y=-4x+2$ we can build a little table (only 2 points are required):

$\begin{array}{c|c}x&y\\0&2\\1&-2\end{array}$

So, if you draw the points (0,2) and (1, -2) and connect them, you'll have your line.

To draw the line $y=-2$ , simply pick any point with y coordinate -2, for example (0, -2), and draw a horizontal line.

Choose the above/below areas as specified above to solve the system.

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3 years ago

Determine the equation of the graph with the coordinates of (4, -1)

Anon25 [30]

Answer:

The required equation of the graph with the coordinates of (4, -1) will be:

$y=\left(x-4\right)^2-1$

The graph is also attached.

Step-by-step explanation:

Given the coordinates (4, -1)

If we put the coordinate values (4, -1) in the given equations, we determine that only $y=\left(x-4\right)^2-1$ is the valid equation as it satisfies the given coordinate value.

For example, putting (4, -1) in the equation

$y=\left(x-4\right)^2-1$

$\left(-1\right)=\left(4-4\right)^2-1$

$-1=\left(0\right)^2-1$

$-1=0-1$

$-1=-1$

So, the equation $y=\left(x-4\right)^2-1$ is true for the coordinate values (4, -1).

Therefore, the required equation of the graph with the coordinates of (4, -1) will be:

$y=\left(x-4\right)^2-1$

Please check, the graph is also attached.

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Answer:

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Step-by-step explanation:

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3 years ago

3 (3n-4)=3 (n+4) help help​

3 (3n-4)=3 (n+4) help help