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svlad2 [7]
4 years ago
11

Which binomial must be subtracted from (10r-7) so that the difference of the 2 polynomials is (93r+12)?

Mathematics
1 answer:
babunello [35]4 years ago
6 0

First binomial expression is A = (10r - 7).

Let's assume second binomial expression is B.

and third binomial expression is C = (93r + 12).

According to given question, A - B = C.

To find B, we can subtract C from A such that;

B = A - C

B = (10r - 7) - (93r + 12)

Distributing negative sign and removing parentheses;

B = 10r - 7 - 93r - 12

Combining like terms;

B = (10r - 93r) + (-7 -12)

B = (-83r) + (-19)

B = -83r -19

Hence, second binomial expression would be B = (-83r -19).

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adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\&#10;\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\&#10;\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\&#10;\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\&#10;\mathsf{8x-32-9x+45=5}\\\\&#10;\mathsf{8x-9x=5+32-45}\\\\&#10;\mathsf{-x=-8}\\\\&#10;\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

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Answer:

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