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masha68 [24]
3 years ago
5

What is the lateral surface area of the pyramid?

Mathematics
1 answer:
Delicious77 [7]3 years ago
6 0

Answer:

1,536 square centimeters

Step-by-step explanation:

The formula for the Lateral surface area of the pyramid =

1/2 × perimeter of the square base × slant height

Square base = 32cm

Slant height = 24cm

Perimeter of the square base = (4 × length of the square base side)

4 × 32cm = 128cm

Lateral Surface Area = 1/2 × 128cm × 24cm

= 1,536 square centimeters

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Help if u know it please!!!
Ulleksa [173]
Mean: add all the numbers, then dived the sum by hwo many numbers there are.
72.3 + 74.5 + 81.1 + 72.3 + 75.6 + 79 = 754.8
754.8 ÷ 6 = 75.8
Mean = 75.8°

Median: Put all the number in order from lowest to highest. The middle number is the median. If there are two numbers in the middle, add them then divide the sum by 2.
72.3, 72.3, 74.5, 75.6, 79, 81.1
74.5 + 75.6 = 150.1
150.1 ÷ 2 = 75.05 ~ 75
Median = 75°
5 0
3 years ago
sara says. "if you subtract 14 from my number and multiply the difference by -4, the result is -80." What is Sara's number?​
statuscvo [17]

Answer:

6

Step-by-step explanation:

-80/-4=20+14=6

5 0
3 years ago
Read 2 more answers
Prove that root 7 is irrational by the method of contradiction
Alchen [17]

Let assume that \sqrt7 is a rational number. Therefore it can be expressed as a fraction \dfrac{a}{b} wherea,b\in\mathbb{Z} and \text{gcd}(a,b)=1.

\sqrt7=\dfrac{a}{b}\\\\7=\dfrac{a^2}{b^2}\\\\a^2=7b^2

This means that a^2 is divisible by 7, and therefore also a is divisible by 7.

So, a=7k where k\in\mathbb{Z}

(7k)^2=7b^2\\\\49k^2=7b^2\\\\7k^2=b^2

Analogically to a^2=7b^2 ------- b^2 is divisible by 7 and therefore so is b.

But if both numbers a and b are divisible by 7, then \text{gcd}(a,b)=7 which contradicts our earlier assumption that \text{gcd}(a,b)=1.

Therefore \sqrt7 is an irrational number.

8 0
3 years ago
Help pls <br> Show workings
vitfil [10]

- the type of pair is vertical angle.

- to find x:

-- vertical angles are equal.

4x + 10 = 5x - 1

10 = x - 1

x = 11

6 0
3 years ago
What are the 1st and 3rd quartiles?<br> what is the interquartile range?
FrozenT [24]

Answer:

The first quartile is 5

The third is 8

The interquartile is the difference between the first and third quartile.

The interquartile is 3

Step-by-step explanation:

First, make a list of all the numbers. To find the first quartile, you have to first find the median. The median is the first 7 in the list.

Everything before 7 is the lower percentile of the range.

The firsr quartile is the median of the lower percentile.

The lower list is:

2,3,4,4,5,6,6,6

The median of this list is 5.

The process for finding the third quartile is the same except the list is the higher percentile which is the list of numbers above the median.

7 0
3 years ago
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