Suppose that the proportion of the white crest alleles (r) is given by w and that of the Red crest allele (R) is given by p. We have that p+w=1. The probability that an individual has 2 r alleles is given by w*w since for each allele position the probability is w. Only these individuals have a White phenotype. Hence, we get that w^2=
; the right hand side is the proportion of white birds in the total population. Doing the calculations, this yields that w=0.37. From this, we calculate that p=0.63. The possible ways we have heterozygous individuals are the combinations Rr and rR. The probability for each of those is p*w. Thus, the total probability is 2pw. This is equal to 0.466=0.47. This is the fraction of the future population that is going to be heterozygous assuming the conditions of the Handy-Weinberg equilibrium like random reproductive matching etc.
2. All cells arise from pre existing cells(Rudolf Virchow). Cell is the fundamental, structural and functional unit of all organisms(Schleiden and Schwann).
3. All cells have a cell membrane.
All cells have chromosomes present.
All cells have cytoplasm.
4.Eukaryotic cells contain a nuclear membrane but Prokaryotic cells have only pseudo nucleus
Eukaryotic cells contain membrane bound organelles but prokaryotic cells don't.
ATP( adenosine triphosphate )
Answer:
D. Alternative splicing is the mechanism that produce complexity in the genes by splicing some of the protein coding part (exons) of a genes
Explanation:
There are certain splicing enhancers sites present in Exons which facilitiates the binding of RNA binding protein specifically SR protein family rich in Serine and Arginine residues. This SR protein will help in splicing of exons.
The significance of this type of mechanism is the ability of a cell to produce an isoform of protein which have retain their function.
This mechanism also help is diversity or in short in evolution.
The likelihood that the first two offspring of the cross will have congenital analgesia would be 1/16
<h2>Autosomal Recessive Traits</h2>
For autosomal recessive traits, two recessive alleles are needed for the trait to manifest while one recessive allele means heterozygosity.
In this case, let us assume that congenital analgesia is represented by the allele b; heterozygous individuals will, thus, be Bb.
Bb x Bb
BB Bb Bb bb
Probability of producing unaffected offspring = 3/4
Probability of producing affected offspring = 1/4
Likelihood of the first two offspring having congenital analgesia = probability of first having congenital analgesia and the second having congenital analgesia
= 1/4 x 1/4
= 1/16
More on genetical probabilities can be found here: brainly.com/question/851793?referrer=searchResults
