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3 years ago

Solve for x Please help me

Mathematics

1 answer:

Sedbober [7]3 years ago

4 0

9514 1404 393

Answer:

x = 8.2

Step-by-step explanation:

As indicated on the supplied diagram, the measure of arc GH is ...

GH = 360° -83° -115° = 162°

The inscribed angle at F is half this measure, so we have ...

(10x -1)° = 162°/2

10x = 82 . . . . . . . . add 1 and simplify

x = 8.2 . . . . . . . . . divide by 10

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3 years ago

Write an equivalent expression for the 4th root of 324m^12 * the cubed root of 64k^9. Need help!

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Answer:

The equivalent expression to the givan expression is

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Step-by-step explanation:

Given expression is 4th root of 324m^12 * the cubed root of 64k^9

The given expression can be written as

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}$

To find the equivalent expression to the given expression :

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}$

$=\sqrt[4]{81\times 4m^{12}}\times\sqrt[3]{16\times 4k^9}$

$=\sqrt[4]{3\times 3\times 3\times 3\times 4m^{12}}\times\sqrt[3]{4\times 4\times 4k^9}$

$=(3\times \sqrt[4]{m^{12}})\times (4\times \sqrt[3]{k^9})$

$=(3\times \sqrt[4]{4m^{12}})\times (4\times \sqrt[3]{k^9})$

$=(3\times \sqrt[4]{4}\times (m^{12})^{\frac{1}{4}})\times (4\times {(k^9)^{\frac{1}{3}})$

$=(3\sqrt[4]{4}\times m^{\frac{12}{4}})\times (4\times k^{\frac{9}{3}})$

$=(3\sqrt[4]{4}\times m^3)\times (4\times k^3)$

$=3\sqrt[4]{4}m^3.4k^3$

$=12\sqrt[4]{4}m^3k^3$

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

Therefore the equivalent expression to the given expression is

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

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3 years ago

-2(n+3)+3n please help it’s do in less than 8 hours

saveliy_v [14]

Answer:

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Step-by-step explanation:

Firsly, break the bracket and you will get:

-2(n+3)+3n

= -2 * n + 3 * (-2) + 3n

= -2n + (-6) + 3n

= -2n + 3n - 6

= n - 6

Hope this helped :3

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3 years ago