<span><span>x^2+y^2=9 (an equation of a circle with a radius of 3)</span>sin(x)+cos(y)=0.52x-3y=1cos(x^2)=y(x-3)(x+3)=y^2<span>y=x^2</span></span>
I’m pretty sure his speed is 1 mile per hour. hope this helps you!
Answer:
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To find the range, you need to locate the vertex:
equation for vertex = ax^2 + bx +c
in x^2 + 3, a = 1, b = 0 and c = 3
now vertex form = a(x+d)^2 +e
d = b/2a = 0/2*1 = 0
e = c-b^2/4a = 3-0^2/4*1 = 3
The equation becomes: (x+0)^2 +3.
The range is Y ≥ 3 ( greater than or equal to 3)
Answer:
Step-by-step explanation:
The triangle is a right triangle.
We can use trigonometric functions to solve the problem.
tan θ = opp/adj
tan 30 = y/(4√3)
y = 4√3 tan 30
y = 4