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2 years ago

(100 POINTS) URGENT PLEASE HELP

Mathematics

1 answer:

zhenek [66]2 years ago

8 0

Answer:

I'm not sure but I'll try help you work it out

Step-by-step explanation:

You need to do 300 x 0.75

Then you need to do 0.75 + 0.75, 300 x 1.50

Now compare the answers

A reasonable domain could be a bake sale <3

Sorry I tried to help

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A building contractor examined 6 floor joists in a home and found that they had the following widths:

miss Akunina [59]

Answer:

Step-by-step explanation:8 inches

89 is the answe 89

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3 years ago

A car travels the 120 miles from A to B at 60 miles per hour, and then returns to A on the same road. If the average rate of the

inessss [21]

Outbound Trip 120 miles 60 mph equals 2 hours

Return Trip 120 miles

Total Trip 240 miles at 45 mph average speed

Total time = distance / rate = 240 / 45 = 5.3333333333 Hours

The return trip of 120 miles takes (5.3333333333 Hours MINUS 2 hours)

Return Trip Speed = 120 / 3.333333333 = 36 miles per hour

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4 years ago

Answer fast again important

gtnhenbr [62]

Answer: 17 square inches.

Step-by-step explanation: Area of a triangle is 1/2 x b x h. We can just take the area of half of the whole triangle, and double it. In this case, half of the triangle has an area of 1/2 x 3.4 x 5 = 8.5. Doubling it is the same is doing 8.5 x 2, which equals 17.

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3 years ago

Sasha is collecting cans to recycle.When she collected 180 cans she knew she haad reached 60% of her goal How many more cabs doe

Arturiano [62]

It would be 60 because 180 minus 60 is 60

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3 years ago

g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o

natali 33 [55]

Answer:

The tangent line to the given curve at the given point is $y=9x-26$ .

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of $y=2x^2-7x+6$ and then evaluate it for $x=4$ .

$(y=2x^2-7x+6)'$ Differentiate the equation.

$(y)'=(2x^2-7x+6)'$ Differentiate both sides.

$y'=(2x^2)'-(7x)'+(6)'$ Sum/Difference rule applied: $(f(x)\pmg(x))'=f'(x)\pm g'(x)$

$y'=2(x^2)'-7(x)'+(6)'$ Constant multiple rule applied: $(cf)'=c(f)'$

$y'2(2x)-7(1)+(6)'$ Applied power rule: $(x^n)'=nx^{n-1}$

$y'=4x-7+0$ Simplifying and apply constant rule: $(c)'=0$

$y'=4x-7$ Simplify.

Evaluate y' for x=4:

$y'=4(4)-7$

$y'=16-7$

$y'=9$ is the slope of the tangent line.

Point slope form of a line is:

$y-y_1=m(x-x_1)$

where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

Insert 9 for $m$ and (4,10) for $(x_1,y_1)$ :

$y-10=9(x-4)$

The intended form is $y=mx+b$ which means we are going need to distribute and solve for $y$ .

Distribute:

$y-10=9x-36$

Add 10 on both sides:

$y=9x-26$

The tangent line to the given curve at the given point is $y=9x-26$ .

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function $f(x)=2x^2-7x+6$ at $x=4$ (the slope of the tangent line at $x=4$ ):

$\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}$

$\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}$ We are given f(4)=10.

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

$2x^2-7x-4=(x-4)(2x+1)$

Let's check this with FOIL:

First: $x(2x)=2x^2$

Outer: $x(1)=x$

Inner: $(-4)(2x)=-8x$

Last: $-4(1)=-4$

---------------------------------Add!

$2x^2-7x-4$

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

$\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}$

$\lim_{x \rightarrow 4}(2x+1)$

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0

4 years ago