The largest number of different whole numbers that can be on Zoltan's list is 999
<h3>How to determine the largest number?</h3>
The condition is given as:
Number = 1/3 of another number
Or
Number = 3 times another number
This means that the list consists of multiples of 3
The largest multiple of 3 less than 1000 is 999
Hence, the largest number of different whole numbers that can be on Zoltan's list is 999
Read more about whole numbers at:
brainly.com/question/19161857
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➷ I'm assuming the answer is to be left in algebraic form.
Perimeter = length + length + width + width or (2 x length) + (2 x width)
Substitute the values in:
Perimeter = 2(3x - 5y - 4z) + 2(x - 3y + 5z)
Simplify:
Perimeter = 6x - 10y - 8z + 2x - 6y + 10z
Perimeter = 8x - 16y + 2z <== this is the answer
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Answer: The answer is “10cm”
Step-by-step explanation: To get to this answer we first need to know the formula for find the hypotenuse which is a^2 + b^2 = c^2. A and B are the two sides in this case a and b are 8 cm and 6 cm. Then you plug in the values into the equation, it looks like this 8^2 + 6^ = c^2 once you solve you get 64 + 36 = c. When you add 64 and 36 you get 100 but their is one more step. You must find the square root of 100 which is 10. So your answer for the hypotenuse is “10cm”
Have a nice day!
Answer:
9c - 13
Step-by-step explanation:
Given
3(c - 7) + 2(3c + 4) ← distribute both parenthesis
= 3c - 21 + 6c + 8 ← collect like terms
= 9c - 13
There’s no answer choices but i got log(28•3^1/3)
