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seraphim [82]
3 years ago
11

Please help me quiz

Mathematics
1 answer:
velikii [3]3 years ago
5 0
Answer would be the bottom answer
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What is X? Because it -18+ 3x+x=-4x+50
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Identify the type of pair of angles labeled as 1 and 2 in the figure.
myrzilka [38]

<em>Hey</em><em>!</em><em>!</em>

<em>1</em><em> </em><em>and </em><em>2</em><em> </em><em>are</em><em> </em><em>vertical</em><em> </em><em>angles</em><em>.</em>

<em>Vertically</em><em> </em><em>opp</em><em>osite</em><em> </em><em>angles</em><em> </em><em>are</em><em> </em><em>always</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em><em>each</em><em> </em><em>other</em><em>.</em>

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3 years ago
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What is this shape? (sorry I'm d.umb)
Harrizon [31]

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triangular prism

Step-by-step explanation:

3 0
3 years ago
Write a polynomial of degree 5 with zero x=0,i square root 7, -2i
professor190 [17]

Answer:

P(x)=x^5+11x^3+28x

Step-by-step explanation:

<u>Roots of a polynomial</u>

If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

P(x)=a(x-x_1)(x-x_2)(x-x_3)...(x-x_n)

Where a is an arbitrary constant.

We know three of the roots of the degree-5 polynomial are:

x_1=0;\ x_2=\sqrt{7}\boldsymbol{i}:\ x_3=-2\boldsymbol{i}

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

x_4=-\sqrt{7}\boldsymbol{i}:\ x_3=+2\boldsymbol{i}

Let's build up the polynomial, assuming a=1:

P(x)=(x-0)(x-\sqrt{7}\boldsymbol{i})(x+\sqrt{7}\boldsymbol{i})(x-2\boldsymbol{i})(x+2\boldsymbol{i})

Since:

(a+b\boldsymbol{i})\cdot (a-b\boldsymbol{i})=a^2+b^2

P(x)=(x)(x^2+7)(x^2+4)

Operating the last two factors:

P(x)=(x)(x^4+11x^2+28)

Operating, we have the required polynomial:

\boxed{P(x)=x^5+11x^3+28x}

7 0
3 years ago
This one is really hard
Oksana_A [137]

Answer:

W=P-2L / 2

Step-by-step explanation:

P=2(L+W)

P=2L+2W

-2L -2L

P-2L=2W

W=P-2L / 2

4 0
3 years ago
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