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Norma-Jean [14]
3 years ago
5

How do I do this? Brainliest for best answer!

Mathematics
1 answer:
denis-greek [22]3 years ago
7 0
If you replace 2 with x you will get 1 = 1

This means the anwser is :
x = 2

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If f(x)=5x-25 and g(x) = 1/5x+5 which expression could be used to verify g(×) is the inverse of f(×)
Gelneren [198K]

Answer:

The  expression could be used to verify g(x) is the inverse of f(x) is letter b which is 1/5(5x-25)+5

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
Mrs. Bogaczyk got bored and decided to go on an Amazon spending spree! She bought 3 pairs of flip flops for $14.95 each, a sundr
Dovator [93]

Step-by-step explanation:

3 pairs of flip flops = 14.95 x 3 = 44.85

Total amount spent = 44.85 + 21.50 + 9.99 + 15. 44 = 91.78

After adding tax = 91.78 + 7.34 = 99.12

Mrs B spent 99.12 altogether

Budget = 100

Then money left = 100 - 99.12 = 0.88

8 0
3 years ago
Calculate the volume of the right rectangular prism shown. <br><br> Edulastic Question
Marysya12 [62]

since we have the area of the front side, to get its volume we can simple get the product of the area and the length, let's firstly change the mixed fractions to improper fractions.

\stackrel{mixed}{23\frac{2}{3}}\implies \cfrac{23\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{71}{3}} ~\hfill \stackrel{mixed}{4\frac{7}{8}}\implies \cfrac{4\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{39}{8}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{71}{3}\cdot \cfrac{39}{8}\implies \cfrac{71}{8}\cdot \cfrac{39}{3}\implies \cfrac{71}{8}\cdot 13\implies \cfrac{923}{8}\implies 115\frac{3}{8}~in^3

5 0
2 years ago
How many times can 2 go into 35
USPshnik [31]

Answer:

17.5

Step-by-step explanation:

Just use the equation 35÷2 to find how many times 2 can go into 35

7 0
3 years ago
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on tuesday a local hamburger shop sold a combined total of 348 hameburgers and cheeseburger. the number of cheeseburger sold was
ANTONII [103]

Answer:

There were 261 Cheeseburgers and 87 Hamburgers sold on Tuesday

Step-by-step explanation:

Lets write some equations where H=Hamburgers and C=Cheeseburgers:

1) H+C=348

2) C=3H

1) Substitute 3H as C in the first equation:

3H+H=348

2) Combine alike terms:

4H=348

3) Divide both sides by 4:

H=87

4) Now, substitute 87 as H in the first equation:

87+C=348

5) Subtract 87 from both sides:

C=261

6 0
3 years ago
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