A two-way frequency table is shown below displaying the relationship between age and preferred cola beverage. We took a sample o
f 100 people and recorded the following results:
Cola Rootbeer Dr. Fizz TOTAL
10-25 10 5 20 35
26-40 15 10 10 35
41-55 20 10 0 30
TOTAL 45 25 30 100
What is the probability (rounded to the nearest whole percent) that a randomly selected person is 41-55 in age or prefers drinking Dr. Fizz?
55%
35%
60%
0%
Cola Rootbeer Dr. Fizz TOTAL
10-25 10 5 20 35
26-40 15 10 10 35
41-55 20 10 0 30
TOTAL 45 25 30 100
What is the probability (rounded to the nearest whole percent) that a randomly selected person is 41-55 in age or prefers drinking Dr. Fizz?
55%
35%
60%
0%
1 answer:
Answer:
60%
Step-by-step explanation:
The table with proper formatting is attached below.
We have to find the probability that a randomly selected person is 41-55 in age or prefers drinking Dr. Fizz.
Total number of people = 100
People in range 41 - 55 = 30
People who prefer Dr. Fizz = 30
People in range of 41 - 55 and prefer Dr. Fizz = 0
The general formula of probability in case of OR of two events is:
P ( A or B ) = P(A) + P(B) - P( A and B)
So for the given case we can write:
P (Person is in 41-55 range OR prefer Dr. Fizz) = P (Person is in 41 - 55 range) + P(Prefers Dr. Fizz) - P(Is in 41-55 range And prefers Dr. Fizz)
P (Person is in 41-55 range OR prefer Dr. Fizz) = 30/100 + 30/100 - 0/100
= 60/100
= 60%
Thus there is a 60% probability that a randomly selected person is 41-55 in age or prefers drinking Dr. Fizz
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