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Hunter-Best [27]
3 years ago
15

Suppose you want to estimate the proportion of polydactyl cats (cats with extra toes). You sample 419 randomly selected cats, an

d find 56 polydactyls. You have no prior assumption to test- you only want to estimate the proportion. Should you carry out a hypothesis test using the sample proportion 56/419 as your null hypothesis? Select the best answer. Yes. Your null should be: The proportion of cats who are polydactyl is 56419, or 13.4%. 0 A. No. You should have a null hypothesis that the proportion of cats who are polydactyl is 0, since it's a genetic defect. O B. ° C. No. 419 isn't 10 times larger than 56. O D. No. There's no way to get a truly random sample. No. When all you wantto do isestimate a population parameter, you should construct a confidence interval. E. O F. I'm not sure.
Mathematics
1 answer:
german3 years ago
6 0

Answer:

No. When all you want to do is estimate a population parameter, you should construct a confidence interval.

Step-by-step explanation:

In this case, there is no other prior estimation about the population to test (a hypothesis to nullify). The only thing you can do is construct a confidence interval of the proportion, where the standard deviation can be calculated in function of the proportion and the sample size.

The right answer is E: "No. When all you want to do is estimate a population parameter, you should construct a confidence interval."

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Find the value of y<br> X=4/y + 2
Oduvanchick [21]

Answer:

Step-by-step explanation:

5 0
3 years ago
Given that a function, h, has a domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25 and that h(8) = 19 and h(-2) = 2, select the
AveGali [126]

The true statement is h(2)=16.

<h3 /><h3>What is domain and range?</h3>

The domain of a function is the set of values that we are allowed to plug into our function. The range of a function is the set of values that the function assumes.

Given:

domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25,

Also, h(8) = 19 and h(-2) = 2,

Now,

2=h(-2)< h(2)<h(8) =19

h(8)=19≠21

h(13)> h(8) =19

h(-3)< h(-2) =2  [1 ≤ h(x) ≤ 25]

Hence, h(2)=16

Learn more about domain and range:

brainly.com/question/23199615

#SPJ1

5 0
2 years ago
HELP ASAP!!
garri49 [273]
I'm pretty sure it would be <span>x - y + 1 = 0 because if you plug in one of the coordinates into each equation, this is the only one that works.

</span><span>y - x + 1 = 0
2 - 1 + 1 = 0
2 = 0 not correct

</span><span>x - y + 1 = 0
1 - 2 + 1 = 0
0 = 0 correct

</span><span>-x - y + 1 = 0
-1 - 2 + 1 = 0
-2 = 0 not correct
</span>
4 0
3 years ago
E=mc2 Solve for C<br><br> Can someone help me solve for C?
zepelin [54]
C = sqrt(e/m)

You can get this by first dividing away the m and then taking the square root of both sides. 
4 0
3 years ago
Read 2 more answers
Please can someone help me answer the question in the picture
Firdavs [7]
(X+3)(x+7) X+7
————— = ——
(X-3)(x+3) X-3
7 0
3 years ago
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