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Hunter-Best [27]
3 years ago
15

Suppose you want to estimate the proportion of polydactyl cats (cats with extra toes). You sample 419 randomly selected cats, an

d find 56 polydactyls. You have no prior assumption to test- you only want to estimate the proportion. Should you carry out a hypothesis test using the sample proportion 56/419 as your null hypothesis? Select the best answer. Yes. Your null should be: The proportion of cats who are polydactyl is 56419, or 13.4%. 0 A. No. You should have a null hypothesis that the proportion of cats who are polydactyl is 0, since it's a genetic defect. O B. ° C. No. 419 isn't 10 times larger than 56. O D. No. There's no way to get a truly random sample. No. When all you wantto do isestimate a population parameter, you should construct a confidence interval. E. O F. I'm not sure.
Mathematics
1 answer:
german3 years ago
6 0

Answer:

No. When all you want to do is estimate a population parameter, you should construct a confidence interval.

Step-by-step explanation:

In this case, there is no other prior estimation about the population to test (a hypothesis to nullify). The only thing you can do is construct a confidence interval of the proportion, where the standard deviation can be calculated in function of the proportion and the sample size.

The right answer is E: "No. When all you want to do is estimate a population parameter, you should construct a confidence interval."

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Which is the reciprocal of the mixed number, 5 5/6 ?
kirill [66]

Answer:

6/35

Step-by-step explanation:

5 5/6 = 35/6, the inverse would be 6/35

3 0
2 years ago
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Explain how you can use a 10 by 10 grid to model 42%
tia_tia [17]

a 10-by-10 grid means there are 100 squares and percent is out of 100 so if you have 42% then you just need to fill in 42 squares

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2 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
Need help figuring out the values of x and y for 11-13 please and thank you!!
Ne4ueva [31]

11 is 110 for x and y

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13 is also 90 degrees for x and y

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Graph the image of the figure after a dilation with a scale factor of 2 centered at (-7, - 2).
tigry1 [53]

Answer:

Sorry this is late!

Step-by-step explanation:

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