Some ppl might think this is easy

The difference of a number times 2 and 3 equals 8.

laiz [17]

I think the answer is 2 but I'm not sure

8 0

3 years ago

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Someone help me on this math problem.

timofeeve [1]

If M is a midpoint of PQ, then we can use the formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

We have the endpoints (-2a, 0) and (0, 2b). Substitute:

$\dfrac{-2a+0}{2}=\dfrac{-2a}{2}=-a\\\\\dfrac{0+2b}{2}=\dfrac{2b}{2}=b$

<h3>Answer: M(-a, b)</h3>

4 0

3 years ago

What percent is 25 of 100?

vova2212 [387]

25%... so yea it's just 25/100 that's 1/4 which is 25%

5 0

3 years ago

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Tim claims that a coin is coming up tails less than half of the time. In 110 tosses, the coin comes up tails 47 times. Using P-v

lilavasa [31]

Answer:

$z=\frac{0.427 -0.5}{\sqrt{\frac{0.5(1-0.5)}{110}}}=-1.531$

$p_v =P(z$

If we compare the p value obtained and using the significance level given $\alpha=0.1$ we have that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of tails is significantly less than 0.5.

Step-by-step explanation:

1) Data given and notation

n=110 represent the random sample taken

X=47 represent the number of tails obtained

$\hat p=\frac{47}{110}=0.427$ estimated proportion of tails

$p_o=0.5$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion of tails is lower than 0.5:

Null hypothesis: $p\geq 0.5$

Alternative hypothesis: $p < 0.5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.427 -0.5}{\sqrt{\frac{0.5(1-0.5)}{110}}}=-1.531$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

If we compare the p value obtained and using the significance level given $\alpha=0.1$ we have that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of tails is significantly less than 0.5.

6 0

3 years ago

out of a swarm of bees one fifth part settled on a kadamba blossom; one third on a silihindra flower; three times the difference

Lisa [10]

setting things up:<em>
let x be the # of bees in the swarm, then </em>
$\frac{x}{5}+\frac{x}{3}+3(\frac{x}{3}-\frac{x}{5})+1=x$

<span><em>multiply across by 15</em>
</span> $3x+5x+3(5x-3x)+15=15x$
$8x+3(2x)+15=15x$
$8x+6x+15=15x$
$14x+15=15x$
$15=x\leftrightarrow x=15$

5 0

3 years ago