What value of b makes the polynomial x2+bc+16 a perfect square
1 answer:
For a perfect square
b² = 4*a*c
Comparing ax² + bx + c = 0 to x² + bx + 16
a = 1, c = 16
<span>b² = 4*a*c
</span>
<span>b² = 4*1*16
</span>
<span>b² = 64
</span>
b = √64
b = 8
The value of b = 8.
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