What value of b makes the polynomial x2+bc+16 a perfect square
1 answer:
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Answer:
690 - 595
Step-by-step explanation:
As we know that representation of a 3 digit number = xyz
where x 0
z is at ones place
y is at tens place
x is at hundred place
As, we have to subtract two 3 digits numbers with different hundred digits
So, Let
The hundred digit of first number be 6
The hundred digit of second number be 5
∴
Assume first number with hundred digit 6
Let the number be - 690
Now,
Assume second number with hundred digit 5
Let the number be - 595
Now,
We will check that the difference between both the numbers are less than 100 or not
Now,
690 - 595 = 95 < 100
It satisfies the condition
So, the equation becomes 690 - 595