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Ahat [919]
3 years ago
5

Find the slope and y-intercept of the line that is \green{\text{parallel}}parallelstart color #28ae7b, start text, p, a, r, a, l

, l, e, l, end text, end color #28ae7b to \blue{y = -2 x - 5}y=−2x−5start color #6495ed, y, equals, minus, 2, x, minus, 5, end color #6495ed and passes through the point \red{(-3, -3)}(−3,−3)start color #df0030, left parenthesis, minus, 3, comma, minus, 3, right parenthesis, end color #df0030.
Mathematics
1 answer:
Papessa [141]3 years ago
8 0

Answer:

m=1 b=2.

Step-by-step explanation:

The equation of the perpendicular line is \green{y = x + 2}y=x+2

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Softa [21]

Answer:

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Step-by-step explanation:

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2 years ago
Need help with inscribed angles If M
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Given:

In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and m\angle BCD=30^\circ.

To find:

The m\angle AOB.

Solution:

If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.

We have, DC is parallel to BA and BC is the transversal line.

\angle OBA\cong \angle BCD        [Alternate interior angles]

m\angle OBA=m\angle BCD

m\angle OBA=30^\circ

In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.

We know that base angles of an isosceles triangle are congruent.

\angle OAB\cong \angle OBA      [Base angles of an isosceles triangle]

m\angle OAB=m\angle OBA

m\angle OAB=30^\circ

In triangle AOB,

m\angle OAB+m\angle OBA+m\angle AOB=180^\circ

30^\circ+30^\circ+m\angle AOB=180^\circ

60^\circ+m\angle AOB=180^\circ

m\angle AOB=180^\circ-60^\circ

m\angle AOB=120^\circ

Therefore, the measure of angle AOB is 120 degrees.

6 0
2 years ago
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Maslowich

Answer:

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Step-by-step explanation:

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Answer: 31.25 ft

Step-by-step explanation:

50 / 32 = x / 20

32x = 50(20)

x = 31.25 ft

7 0
2 years ago
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