The answer to the problem "Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius" is A = (160/3 π + 16 √3) inches². Thank you for posting your question. I hope this answer helped you. Let me know if you need more help.
Let the solutions be a and b.
a = -2; b = -10
a + b = -2 + (-10) = -12
ab = (-2)(-10) = 20
(x - a)(x - b) = 0
(x - (-2))(x - (-10)) = 0
(x + 2)(x + 10) = 0
x^2 + 10x + 2x + 20 = 0
x^2 + 12x + 20 = 0
-h = 12
h = -12
4k = 20
k = 5
IdkAnswer:
Step-by-step explanation:
