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3 years ago

We want to find the zeros of this polynomial p(x)= ( x^2-1)(x^2-5x+6)

Mathematics

1 answer:

Scrat [10]3 years ago

4 0

Answer:

see explanation

Step-by-step explanation:

To find the zeros let p(x) = 0 , that is

(x² - 1)(x² - 5x + 6) = 0

Factorise each factor

x² - 1 ← is a difference of squares and factors as (x - 1)(x + 1)

x² - 5x + 6 = (x - 2)(x - 3), thus

(x - 1)(x + 1)(x - 2)(x - 3) = 0

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x + 1 = 0 ⇒ x = - 1

x - 2 = 0 ⇒ x = 2

x - 3 = 0 ⇒ x = 3

The zeros are x = ± 1, x = 2, x = 3

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Consider the system of equations: Equation 1: -2x + 3y=9 Equation 2 : -8.1 – 7y = 10 Before adding the equations together, which

diamong [38]

The first option :

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3 years ago

Mrs. Sloan draws two figures on the board.

Trava [24]

A dilated shape will either be enlarged or compressed.

<em>Allen did not make any mistake, and the scale factor is 3.</em>

The dimension of the smaller rectangle (figure Z) is:

3 units by 4 units

The corresponding dimension of the bigger rectangle (figure Z') is:

9 units by 12 units

The scale factor (k) is calculated by dividing the dimensions of Z' by Z.

So, we have:

$k = \frac{9}{3}$

$k = 3$

$k = \frac{12}{4}$

$k = 3$

Notice that both values of k are the same (i.e. 3)

This means that the scale factor is 3

Also figure Z and Z' share the same center of origin at point X

This means that the center of dilation from Z to Z' is X

Hence,

Allen made no mistake, and she is correct about the scale factor.