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Vilka [71]
3 years ago
13

examine the variety of shapes below if a shape has shading then find the area of the Shaded region ​

Mathematics
1 answer:
Svetach [21]3 years ago
6 0

<em>only the last figure (i.e figure e) is shaded </em>

The shaded region is a triangle

Area of a triangle

= ½ × b × h

= ½ × 14 × 5

= ½ × 70

= 35yd²

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1. Gummy worms are $3.50 per pound
Alexxandr [17]
The constant of proportionality is 3.50 since gummy worms are sold at the same rate per pound.

3.50x, equation
3.50(2.5) = $8.75 for 2.5 pounds
3 0
3 years ago
A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
I really really need help with this . No links
Diano4ka-milaya [45]

Answer:

pretty sure its 123

Step-by-step explanation:

3 0
3 years ago
2. Stephanie has a bag of candy with 2 snickers, 3 butterfingers, 2 Reese's, and 3 Milky Ways bars. What is the probability that
PtichkaEL [24]

I'm sorry to answer your question without an answer but I have no result but if I get one I will notify you

Step-by-step explanation:

I hope that help's SORRY!!

7 0
3 years ago
19/1000 as a decimal
o-na [289]

Answer:

0.019

Step-by-step explanation:

Just move the decimal places 3 times from the end to get your answer

6 0
3 years ago
Read 2 more answers
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