All categories

3 years ago

Find the value of x. pls solve

Mathematics

1 answer:

dmitriy555 [2]3 years ago

8 0

the answer is x = 120 degrees

You might be interested in

Find the length of the arch

posledela

Use the formula....central angle/360= arc length/2* pie* R
150/360=x/2*3.14*7.5
150/360=x/47.1
360x=7065
x=7065/360
x=19.625 in

8 0

2 years ago

Classify the triangle with side lengths 11 cm, 30 cm, and 39 cm as acute, right, or obtuse

Ahat [919]

Answer:

This triangle is a obtuse traingle.

Step-by-step explanation:

First of all, it is impossible that this triangle is actute since the sides are different length.

Right is also not possible ( in this case ) because there are two pretty far sides.

30, 39

A obtuse triangle have a short side of 11 cm pointing top right and a side of 30 cm pointing directly to the right and the 39 cm side connecting the ends of the other sides.

\ Third side ( 39 cm , the one connecting

First side ( 11 cm ) \ the ends of side 1 and 2)

\______________

Second side ( 30 cm )

<h3><u><em>Please rate this and please give brainliest. Thanks!!! </em></u></h3><h3><u><em>Appreciate it! : )</em></u></h3><h3><u><em></em></u></h3><h2><u><em>And always, </em></u></h2><h2><u><em> SIMPLIFY BANANAS : )</em></u></h2>

5 0

2 years ago

K+3=-9 answers key please

vlabodo [156]

K+3=-9
k=-12 is the answer

7 0

3 years ago

Read 2 more answers

SOMEONE Please HELP me out with theses 2

olchik [2.2K]

Hello!

The answer for #1. is 4 centimeters, because it is the only reasonable answer.
The answer for #2. is 1 millimeter, because the tick is smaller than the penny, which is smaller than any of the other lengths.

I hope this helped :))

4 0

3 years ago

Read 2 more answers

Use Cramer Rule to solve the following system: 8x−5y=70 and 9x+7y=3

nlexa [21]

Answer:

$(x,y) = (5,-6)$

Step-by-step explanation:

$\underline{\textbf{Determinant of a matrix.}}\\\\\text{For a}~ 2 \times 2 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2\\b_1&b_2 \end{vmatrix} = a_1b_2 - a_2b_1\\\\\\\text{For a}~ 3 \times 3 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2&a_3\\ b_1&b_2&b_3\\ c_1&c_2&c_3 \end{vmatrix} = a_1\begin{vmatrix} b_2&b_3\\c_2&c_3 \end{vmatrix} - a_2 \begin{vmatrix} b_1&b_3\\c_1&c_3 \end{vmatrix}+ a_3 \begin{vmatrix} b_1&b_2\\c_1&c_2 \end{vmatrix}\\\\\\$

$~~~~~~~~~~~~~~~~~~=a_1(b_2c_3-b_3c_2) -a_2(b_1c_3-b_3c_1) +a_3(b_1c_2-b_2c_1)$

$\underline{\textbf{Cramer's Rule to solve a system of two equations.}}\\\\\text{Consider the system of two equations:}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_1x + b_1 y= c_1\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_2x +b_2 y = c_2\\\\\text{Here,}\\\\x = \dfrac{D_x}{D}= \dfrac{\begin{vmatrix} c_1&b_1\\c_2&b_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\\\ y= \dfrac{D_y}{D}= \dfrac{\begin{vmatrix} a_1&c_1\\a_2&c_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\$

$\underline{\textbf{Solution:}}\\\\~~~~~~~~~~~~~~~~~~~~~~~8x-5y = 70~~~~~~...(i)\\\\~~~~~~~~~~~~~~~~~~~~~~~9x +7y = 3~~~~~~~...(ii)\\\\\text{Applying Cramer's rule:}\\\\x = \dfrac{D_x}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 70& -5 \\3&7 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{70(7) -(-5)(3)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{490+15}{56+45}\\\\\\~~=\dfrac{505}{101}\\\\\\~~=5$

$y = \dfrac{D_y}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 8& 70 \\9&3 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{(8)(3) -(70)(9)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{24-630}{56+45}\\\\\\~~=-\dfrac{606}{101}\\\\\\~~=-6$

$\textbf{Hence, the solution to the system of equation is}~ (x,y) = (5,-6)$

7 0

1 year ago