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3 years ago

What is the area of the rectangle?

Mathematics

1 answer:

Zolol [24]3 years ago

4 0

Area = lw
So 7(4) =28
Area = 28
The answer is C.

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I need help fast .. Please answer quickly

nirvana33 [79]

Answer:

False

Step-by-step explanation:

6 0

3 years ago

If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.

solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$WX=\sqrt{(-3-(-10))^2+(-1-4)^2}$

$WX=\sqrt{(-3+10)^2+(-5)^2}$

$WX=\sqrt{(7)^2+(-5)^2}$

$WX=\sqrt49+25}$

$WX=\sqrt{74}$

Similarly,

$XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}$

$WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}$

Now,

$WX=WY$

So, triangle is an isosceles triangles.

and,

$WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2$

$WX^2+WY^2=74+74$

$WX^2+WY^2=148$

$WX^2+WY^2=(2\sqrt{37})^2$

$WX^2+WY^2=WY^2$

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

3 0

2 years ago

Which expression is equivalent to

pychu [463]

Answer:

Step-by-step explanation:

i cannot find an answer from the expression but i can guess if you didnt follow pemdas, it would be d

3.5 × 102 is 357

(8 × 10−4) + (6 × 10−4) is 132

132/357= .369 or .37 or 0 simplified

d is 4*10-10

10-10 is 0

4*0 is 0

8 0

3 years ago

If 2/5 of students are boys. Find the percentage of the girls.<br> please help me

jonny [76]

Answer:

Step-by-step explanation:

First divide 2by 5 and multiply the answer by 100. Then subtract the answer by 100

4 0

3 years ago

HELP PLSSSSSSSAS THANKS NO LINK

kumpel [21]

Answer:55mm

Explain:I know

7 0

3 years ago