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Anettt [7]
3 years ago
15

10 is what percent of 60

Mathematics
2 answers:
Alona [7]3 years ago
8 0
Is means equal
x percent is x/100
of means multiplication

So translating what you were given:

\sf{10=\frac{x}{100}\times60}

Solve for x

\sf{10=\frac{60x}{100}}

Simplify it

\sf{10=\frac{3x}{5}}

Multiply both sides by 5/3 to isolate x

\sf{x=\frac{50}{3}}

Your final answer is

\huge{\boxed{\bf{10~is~16.67~percent~of~60}}}

gogolik [260]3 years ago
7 0

Answer: p = 16.66%

Step-by-step-Explanation: The easiest way to solve this is by setting up a proportion. A proportion is simply a pair of equal ratios or two fractions that are equal to one another.

In this case we don't know what the percent is but it's important to understand that <em>percent </em>means out of 100 so our denominator for the first fraction is going to be 100. Since we don't know what the percent is since it's asking us to find the percent, we can represent this as a variable. A variable is a letter that represents any number so let's use <em>p</em>.

So we have our first fraction which is \frac{p}{100} and in a proportion the fractions are equal to one another so we will put an equals sign. Our next fraction is going to be is over of. We can determine which is going to be the is and which is going to be the of by looking at the keywords.

So it says 10 <em>is</em> what percent <em>of</em> 60 so it's already telling us that 10 is going to be the <em>is</em> and 60 is going to be the <em>of</em>. So it will be \frac{10}{60} and we know have two fractions or 2 ratios and it is \frac{p}{100} = \frac{10}{60}.

In order to solve for <em>p</em> we will use cross products so we multiply p by 60 and 10 by 100 so we get 60p = 600.

Now we divide both sides of our equation by 60 in order to isolate <em>p</em> and we find that <em>p = 16.66</em>. In most cases you will round to the hundredths place so we can say that <em>p</em> is equal to approximately.

This means that 10 is approximately 16.66% of the number 60.

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What is the solution of √x-5 = x-11
PIT_PIT [208]
Hey!


To solve x in this equation we must first add five to both sides to get \sqrt{x} on its own.

<em>Original Equation :</em>
\sqrt{x} - 5 = x - 11

<em>New Equation {Added 5 to Both Sides} :</em>
\sqrt{x} =x-6

Now we must square both sides of the equation.

<em>Old Equation :</em>
\sqrt{x} =x-6

<em>New Equation {Changed by Squaring Both Sides} :</em>
x= x^{2} -12x+36

And now we must solve the new equation.

Step 1 - Switch sides
x^{2} -12x+36=x

Step 2 - Subtract x from both sides
x^{2} -12x+36-x=x-x

Step 3 - Simplify
x^{2} -13x+36=0

Now we need to solve the rest of the equation using the quadratic formula.

\frac{-(-13)+ \sqrt{(-13) ^{2}-4*1*36 } }{2*1}

{13+ \sqrt{(-13)^{2}-4*1*36 }=13+ \sqrt{25}

\frac{13+ \sqrt{25}}{2}

\sqrt{25}=5

\frac{13+5}{2}

\frac{18}{2}

9

\frac{-(-13)- \sqrt{(-13) ^{2} -4*1*36} }{2*1}

4

<em>So, this means that in the equation \sqrt{x} -5=x-11,</em>  x = 9  <em>and  </em>x = 4.

Hope this helps!


- Lindsey Frazier ♥
4 0
3 years ago
Using this table below, what is the rate of change? Don't forget to include your units.
NeX [460]
(24,18)(28,21)
slope(rate of change) = (21 - 18) / (28 - 24) = 3/4 <==
3 0
3 years ago
Lexie, a bowler, claims that her bowling score is more than 140 points, on average. Several of her teammates do not believe her,
Crazy boy [7]

Answer:

The  test statistic is  t  = 3.744

Step-by-step explanation:

From the question we are told that

  The population mean is  \mu  =  140

  The  The  level of significance is  \alpha  =  0.05

  The  sample size is  n =  18

   The  null hypothesis is  H_o :  \mu =  140

    The  alternative hypothesis is  H_a  :  \mu > 140

    The sample mean is  \= x  =  155

     The  standard deviation is  \sigma  =  17

Generally the test statistics is mathematically represented as

       t  =  \frac{\= x  - \mu }{ \frac{ \sigma}{ \sqrt{n} } }

substituting values

      t  =  \frac{ 155  - 140 }{ \frac{ 17 }{ \sqrt{18} } }

      t  = 3.744

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Answer:

A stem and leaf plot is not suitable in this data because this data is not kind of data for a stem and leaf plot.

Step-by-step explanation:

If you're finding out the mean for this plot You could use a stem and leaf plot.

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Answer:

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Explaining:

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