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xz_007 [3.2K]
3 years ago
14

How many solutions does the equation 6x = 48? Two None Infinitely many One

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
5 0
One, if you take 48/6 you get x=8 :)

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-6<br><img src="https://tex.z-dn.net/?f=%20-%206%20%2B%203%20%5Ctimes%204%20-%2011" id="TexFormula1" title=" - 6 + 3 \times 4 -
ipn [44]
The answer is -5

Explanation:

-6 + 3 x 4 -11=
-6 + 12 -11=
+ 6 -11 = -5
4 0
3 years ago
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Question 4 of 17
Vlada [557]

Answer:

I think it is A OR D

4 0
3 years ago
Find the length of the following curve. If you have a​ grapher, you may want to graph the curve to see what it looks like.
stepladder [879]

The length of the curve y = \frac{1}{27}(9x^2 + 6)^\frac 32 from x = 3 to x = 6 is 192 units

<h3>How to determine the length of the curve?</h3>

The curve is given as:

y = \frac{1}{27}(9x^2 + 6)^\frac 32 from x = 3 to x = 6

Start by differentiating the curve function

y' = \frac 32 * \frac{1}{27}(9x^2 + 6)^\frac 12 * 18x

Evaluate

y' = x(9x^2 + 6)^\frac 12

The length of the curve is calculated using:

L =\int\limits^a_b {\sqrt{1 + y'^2}} \, dx

This gives

L =\int\limits^6_3 {\sqrt{1 + [x(9x^2 + 6)^\frac 12]^2}\ dx

Expand

L =\int\limits^6_3 {\sqrt{1 + x^2(9x^2 + 6)}\ dx

This gives

L =\int\limits^6_3 {\sqrt{9x^4 + 6x^2 + 1}\ dx

Express as a perfect square

L =\int\limits^6_3 {\sqrt{(3x^2 + 1)^2}\ dx

Evaluate the exponent

L =\int\limits^6_3 {3x^2 + 1} \ dx

Differentiate

L = x^3 + x|\limits^6_3

Expand

L = (6³ + 6) - (3³ + 3)

Evaluate

L = 192

Hence, the length of the curve is 192 units

Read more about curve lengths at:

brainly.com/question/14015568

#SPJ1

7 0
2 years ago
Find the distance between the points given. (0,5) and (-5,0)
galina1969 [7]

Answer:

5\sqrt{2}

Step-by-step explanation:

Calculate the distance between the points using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (0, 5) and (x₂, y₂ ) = (- 5, 0)

d = \sqrt{(-5-0)^2+(0-5)^2}

  = \sqrt{(-5)^2+(-5)^2}

  = \sqrt{25+25} = \sqrt{50} = 5\sqrt{2} ← exact value

5 0
3 years ago
triangle MNO is an equilateral triangle with sides measuring 16 units What is the height of the triangle?
fiasKO [112]

see the attached figure to better understand the problem

we know that

The equilateral triangle has three equal sides

so

in the equilateral triangle ABC

AB=BC=AC=16 units

the height of the triangle is the segment BD

in the right triangle BCD

Applying the Pythagorean Theorem

BC^{2} =BD^{2}+DC^{2}

solve for BD

BD^{2}=BC^{2}-DC^{2}

substitute the values

BD^{2}=16^{2}-8^{2}

BD^{2}=192

BD=\sqrt{192}\ units

therefore

<u>the answer is</u>

the height of the triangle is \sqrt{192}\ units


7 0
3 years ago
Read 2 more answers
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