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xz_007 [3.2K]
3 years ago
14

How many solutions does the equation 6x = 48? Two None Infinitely many One

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
5 0
One, if you take 48/6 you get x=8 :)

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Use the Angle Addition Postulate to find the measure of each angle.
Simora [160]
For number 15 and 16, you just have to find the absolute difference between the two points along the calibration of the protractor.

15. ∠BXC = |B - C| = |140° - 110°| = 30°
16. ∠BXE = |B - E| = |140° - 30°| = 110°

For numbers 20 and 21, apply the Angle Addition Postulate. This is when you add the individual interior angles to equate to the total angle.

20. ∠PQS = ∠PQR + ∠RQS
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5 0
3 years ago
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Answer:

y-6x=-27

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simplify with distributive property

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y=6x-27

take away 6x from both sides

y-6x=-27

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2 years ago
A cylinder has dimensions that give the following ratio.
Lostsunrise [7]

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Step-by-step explanation:

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2 years ago
there are 148 juniors and 272 seniors attending prom this year. if there must be three chaperones per 60 students, how many chap
valkas [14]

21 chaperones are needed for 420 students.

Step-by-step explanation:

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No. of seniors = 272

Total = 148+272 = 420 students

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1 chaperone = \frac{60}{3}=20\ students

Ratio of chaperon to students = 1:20

Let,

x be the number of chaperons for 420 students.

Ration of chaperones to students = x:420

Using proportion

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1:20::x:420

Product of mean = Product of extreme

20*x=420*1\\20x=420\\

Dividing both sides by 20

\frac{20x}{20}=\frac{420}{20}\\x=21

21 chaperones are needed for 420 students.

Keywords: ratio, proportion

Learn more about ratios at:

  • brainly.com/question/4464845
  • brainly.com/question/4522984

#LearnwithBrainly

3 0
3 years ago
Can you help me on question 25?!
Y_Kistochka [10]
The answer would be C
5 0
2 years ago
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