All categories

3 years ago

What is the slope of the line that passes through the points (-10,8)and (-15,-7)

Mathematics

2 answers:

balandron [24]3 years ago

5 0

Answer:

m = 3

Step-by-step explanation:

Use the slope formula to find the slope m .

Tasya [4]3 years ago

4 0

M=3 is the slope to find the m

You might be interested in

How to solve<br>3|8x|+8=80

Hatshy [7]

I wanna say x=3 because 8 times 3 is 24 times 3 is 72 + 8 is 80

3 0

3 years ago

4. Which function has two

lianna [129]

Answer: B) (x - 5)(x + 4)

Step-by-step explanation:

we’re looking for x intercepts at x = 5 and x = -4

x - 5 = 0; x = 5

x + 4 = 0; x = -4

(x - 5)(x + 4) is your answer

6 0

3 years ago

Which property can be used to solve the equation?

frosja888 [35]

Answer:

Step-by-step explanation:

You are dividing, if you think about it every time I do it is the opposite of your equation. Plus you are supposed to multiply on both sides to get the value of d.

8 0

2 years ago

Assume that in january 2013, the average house price in a particular area was $288,400. in january 2002, the average price was $

emmainna [20.7K]

Must be simplified. don;'t really know if we should do distributive property

7 0

3 years ago

A filter filled with liquid is in the shape of a vertex-down cone with a height of 9 inches and a diameter of 6 inches at its op

Alina [70]

Answer: Level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

Step-by-step explanation:

Since we have given that

Height = 9 inches

Diameter = 6 inches

Radius = 3 inches

So, $\dfrac{r}{h}=\dfrac{3}{9}=\dfrac{1}{3}\\\\r=\dfrac{1}{3}h$

Volume of cone is given by

$V=\dfrac{1}{3}\pi r^2h\\\\V=\dfrac{1}{3}\pi \dfrac{1}{9}h^2\times h\\\\V=\dfrac{1}{27}\pi h^3$

By differentiating with respect to time t, we get that

$\dfrac{dv}{dt}=\dfrac{1}{27}\pi \times 3\times h^2\dfrac{dh}{dt}=\dfrac{1}{9}\pi h^2\dfrac{dh}{dt}$

Now, the liquid drips out the bottom of the filter at the constant rate of 4 cubic inches per second, ie $\dfrac{dv}{dt}=-4\ in^3$

and h = 2 inches deep.

$-4=\dfrac{1}{9}\times \pi\times (2)^2\dfrac{dh}{dt}\\\\-9\pi =\dfrac{dh}{dt}\\\\-28.28=\dfrac{dh}{dt}$

Hence, level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

7 0

3 years ago