3 years ago

What is the GCF of the expression a2b2c2 + a2bc2 - a2b2c

Mathematics

1 answer:

LenaWriter [7]3 years ago

5 0

Answer:

a^2bc

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=100%5E%7Bm%7D" id="TexFormula1" title="100^{m}" alt="100^{m}" align="absmiddle" class="latex-f

Ivahew [28]

Answer:

Step-by-step explanation:

hello :

100^m / 1000^n

look : 100 = 10² and 1000 = 10^3

so : 100^m = (10²)^m= 10^2m and 1000^n = ( 10^3)^n = 10^3n

100^m / 1000^n = 10^2m / 10^3n

conclusion : 100^m / 1000^n = (10^(2m-3n)) when : z = 2m-3n

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3 years ago

Pamela rode her bike at a constant rate of 0.1 kilometer per minute. Which table represents y , the number of kilometers Pamela

ArbitrLikvidat [17]

Answer:

B, The second table.

Step-by-step explanation:

If you rode a bike 0.1 Kilometers per minute, and you ride for 5 minutes, you would have biked 0.5 Kilometers, not 0.1 Kilometers.

Hope I helped! Please leave a rating and a comment! :)

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3 years ago

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Katarina makes 2 gallons of punch for her party how many cups of punch did she make

Oduvanchick [21]

Answer:

Step-by-step explanation:

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2 years ago

At the moment a hot cake is put in a cooler, the difference between the cake's and the cooler's temperature is 50° Celsius. This

dybincka [34]

Answer:

$D(t)=50(0.8)^t$

Step-by-step explanation:

We are given that

Initially the difference between the cake's and the cooler's temperature ,a=50 degree Celsius

$r=\frac{1}{5}/min$

We have to find the function that gives the temperature difference in degrees Celsius D(t).

We know that

$D(t)=a(1-r)^t$

Substitute the values

$D(t)=50(1-\frac{1}{5})^t=50(1-0.2)^t$

$D(t)=50(0.8)^t$

This is required function that gives the temperature difference in degrees Celsius.

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3 years ago

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Graph y=-x+2 x-3y=-18

Levart [38]

I really dont know sorry

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3 years ago