Just make the slope as 1/2 remember rise over run and start at 0
A^2 + b^2 = c^2
C is your hypotenuse or the longest side of the triangle; you plug in your values and solve for the missing side:
15^2 + b^2 = 17^2
225 + b^2 = 289
*-225 on both sides to get b by itself*
B^2 = 64
*to get rid of the ^2; you take the square root*
B = sqrt 64
B= 8 <— final answer
Answer:
the answer is 2 + i.
Step-by-step explanation:
Let the square root of 3 + 4i be x + iy.
So (x + iy) (x +iy) = 3 +4i
=> x^2 + xyi + xyi + i^2*y^2 = 3 + 4i
=> x^2 – y^2 + 2xyi = 3 + 4i
Equate the real and complex terms
=> x^2 - y^2 = 3 and 2xy = 4
2xy = 4
=> xy = 2
=> x = 2/y
Substitute in
=> x^2 - y^2 = 3
=> 4/y^2 - y^2 = 3
=> 4 – y^4 = 3y^2
=> y^4 + 3y^2 – 4 = 0
=> y^4 + 4y^2 – y^2 – 4 =0
=> y^2(y^2 + 4) – 1(y^2 + 4) =0
=> (y^2 – 1) (y^2 + 4) =0
Therefore y^2 = 1, we ignore y^2 = -4 as it gives complex values of y.
Therefore y = 1 and x = 2/1 = 2
The required square root of 3 + 4i is 2 + i.
Step 1: Simplify each side, if needed.
Step 2: Use Add./Sub. Properties to move the variable term to one side and all other terms to the other side.
Step 3: Use Mult./Div. ...
Step 4: Check your answer.
I find this is the quickest and easiest way to approach linear equations.
Example 6: Solve for the variable.
Answer: it’s Sara paid 3
Step-by-step explanation:
