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kotegsom [21]
3 years ago
10

Solve the inequality 6(x/2+4) greater than or equal to 9

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
4 0

Answer:

9

Step-by-step explanation:

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State restrictions for the given equation below
Genrish500 [490]

The restriction of the given equation is cos^{2}x =cos^{2} x,  other than 0≤x≤2π.

What is restriction of equation?

Restriction of the equation is the value of domain where the value is limited.

Given,

sin^{2} xcos^{2}x +cos^4x =(1-sinx)(1+sinx)

taking cos^2x common, we get

cos^2x(sin^2x+cos^2x)=1+sinx-sinx-sin^2x

we know

sin^2x+cos^2x=1\\cos^2x=1-sin^2x

we get,

cos^2x=cos^2x

and the restriction is 0≤x≤2π.

To know more restriction, visit:

brainly.com/question/68084

#SPJ1

8 0
1 year ago
55g as a percentage of 2.2kg
Evgesh-ka [11]

Answer:

2.5%

2.2kg=2200g

<u>\frac{x}{100}  \times 2200 = 55 \\ 22x = 55 \\ x = 2.5\%</u>

3 0
3 years ago
Picture provided help!
weqwewe [10]

Answer:

A -60i - 14j

Step-by-step explanation:

u = -9i + 8j

v = 7i + 5j

2u = 2(-9i + 8j) = -18i + 16j

6v = 6(7i + 5j) = 42i + 30j

2u - 6v

(-18i + 16j) - (42i + 30j)

(-18i - 42i) + (16j-30j)

-60i - 14j

5 0
3 years ago
Six hundred paving stones were examined for cracks, and 20 were found to be cracked. The same 600 stones were then examined for
spin [16.1K]

Answer:

a) probability that is cracked=1/30 (3.33%)

b) probability that is discoloured = 29/600 (4.83%)

c) probability that is cracked and discoloured =  11/600 (1.83%)

Step-by-step explanation:

assuming that each stone is equally likely to be chosen then defining the events C= the stone is cracked , D= the stone is discoloured , N= the stone is neither cracked or discoloured, then

P(C)= number of favourable outcomes/total number of outcomes = 20 stones/600 stones = 1/30 (3.33%)

P(D)= number of favourable outcomes/total number of outcomes = 29 stones/600 stones = 29/600 (4.83%)

the probability that is discoloured and cracked is P(C∩D) , where

P(C∪D)=P(C) + P(D)-P(C∩D)

and

P(C∪D)= 1- P(N)

thus

1- P(N)=P(C) + P(D)-P(C∩D)

P(C∩D)= P(N)+P(C)+P(D) -1

replacing values

P(C∩D)= P(N)+P(C)+P(D)=562/600 + 20/600 + 29/600 -1= 611/600 -1 = 11/600

thus

P(C∩D)=  11/600 (1.83%)

3 0
3 years ago
Name all the sets that -8 belongs to
Harlamova29_29 [7]

Answer:

rational and real numbers

8 0
2 years ago
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