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____ [38]
2 years ago
15

What is the surface area of the net? *inches squared*

Mathematics
1 answer:
serious [3.7K]2 years ago
3 0

9514 1404 393

Answer:

  75 in^2

Step-by-step explanation:

The central vertical rectangle (including "ears") has dimensions

  3 in wide by (9+2+2) = 13 in tall

Its area is

  A = LW = (3 in)(13 in) = 39 in^2

__

The two rectangles either side of that have dimensions 2 in by 9 in. The area of each of them is

  A = LW = (2 in)(9 in) = 18 in^2

__

The total net area is the sum of the areas of the parts:

  left rectangle + central rectangle + right rectangle

  = 18 in^2 + 39 in^2 + 18 in^2 = 75 in^2 . . . . surface area of the net

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Murrr4er [49]

Answer:

The equation is:

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Step-by-step explanation:

with the previous exercise we look for the equation for h = f (t)

So the data we have are

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with this the particle f (t) is transformed into

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We know that the maximum value of cos in t will be 0, 1 -cos has minutes, the result will be as follows:

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3 years ago
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Answer:

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3 years ago
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Answer:

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Step-by-step explanation:

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I hope this helps

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