1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bingel [31]
3 years ago
15

Input x=?equation

rt{2x - 6}" alt=" f(x)\sqrt{2x - 6}" align="absmiddle" class="latex-formula">
output f(x)= 10​
Mathematics
1 answer:
Flura [38]3 years ago
6 0

Answer:

f(10)=sqrt(14)

Step-by-step explanation:

f(10) = sqrt(2x-6)

f(10)= sqrt(20-6)

f(10)=sqrt(14) - simplest form, no way to factor it.

You might be interested in
Need Help Please, This One Is A Bit Difficult.
emmainna [20.7K]

Answer: 432 units²

Step-by-step explanation:

The figure is composed by two trapezoids.

The formula for calculate the area of a trapezoid is:

A=\frac{h}{2}(B+b)

Where "B" is the larger base, "b" is the smaller base and "h" is the height.

Let be A_f the area of the figure, A_1 the area of the trapezoid on the left and A_2 the area of the trapezoid of the right. Then the area of the figure will be:

 A_f=A_1+A_2

A_f=\frac{h_1}{2}(B_1+b_1)+\frac{h_2}{2}(B_2+b_2)

Substituting values, you get:

A_f=\frac{16units}{2}(25units+4units)+\frac{10units}{2}(25units+15units)=432units^2

<h3> </h3>

8 0
3 years ago
Read 2 more answers
HELP its urgent.............
irga5000 [103]

Answer:

first blank = 39

second blank = 28

Step-by-step explanation:

11 + __ + 7 + 28 = 85 = 39 + __ + 11+ 7

since,, four terms add upto form 85 out of which two terms (11 and 7) are common. so, the first blank will be filled with 39 and second blank with 28.

8 0
2 years ago
Read 2 more answers
Find the? inverse, if it? exists, for the given matrix.<br><br> [4 3]<br><br> [3 6]
True [87]

Answer:

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Step-by-step explanation:

The inverse of a square matrix A is A^{-1} such that

A A^{-1}=I where I is the identity matrix.

Consider, A = \left[\begin{array}{ccc}4&3\\3&6\end{array}\right]

\mathrm{Matrix\:can\:only\:be\:inverted\:if\:it\:is\:non-singular,\:that\:is:}

\det \begin{pmatrix}4&3 \\3&6\end{pmatrix}\ne 0

\mathrm{Find\:2x2\:matrix\:inverse\:according\:to\:the\:formula}:\quad \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}^{-1}=\frac{1}{\det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}}\begin{pmatrix}d\:&\:-b\:\\ -c\:&\:a\:\end{pmatrix}

=\frac{1}{\det \begin{pmatrix}4&3\\ 3&6\end{pmatrix}}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

\mathrm{Find\:the\:matrix\:determinant\:according\:to\:formula}:\quad \det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}\:=\:ad-bc

4\cdot \:6-3\cdot \:3=15

=\frac{1}{15}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

4 0
3 years ago
Can someone plz help its due soon
Mariana [72]
Hotdog hotdog hotdog hotdog
5 0
2 years ago
Is 7/10 more than 1/2
Bingel [31]
7/10 is bigger because it is more than half
5 0
3 years ago
Other questions:
  • Spatial thinking unit worksheet 2
    14·1 answer
  • What is 1 half plus 2 fifths?
    7·1 answer
  • Which ordered pair is a solution of the equation 2x − y = 9 (-4,1)
    10·1 answer
  • How many times greater is the value of 3 in the product of 34 × 10000 in the value of 3 in 34
    8·1 answer
  • How can u classfiy a quadulaterl​
    5·2 answers
  • Which angle is congruent to angle 1?
    7·1 answer
  • Armando has collection of 25 coins . Of the 25 coins , 11 are nickles. What percent of the coins are nickles ?
    8·1 answer
  • I need help with this problem
    10·2 answers
  • PLEASE HELP ITS TIMED!!!!! PLEASE EXPLAIN THE ANSWER TOO!
    15·1 answer
  • The sum of two numbers is equal to 11 and the difference is 19. What are the two numbers?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!