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3 years ago

Classify the following numbers as Natural, Whole number, irrational, non real, rational

Mathematics

1 answer:

sineoko [7]3 years ago

6 0

Answer:

sqroot(111) is irrational.

Step-by-step explanation:

Natural are 1, 2, 3, 4...

Whole are 0, 1, 2, 3...

Irrational are decimals that don't end or repeat. Sqroot(111) is 10.535653752...

Nonreal have an i, the imaginary number.

Rational are fractions (or can be written as a fraction) or decimals that end or repeat.

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coldgirl [10]

Cos(x) = 32/40 = 0.8 ⇒ x ≈ 37°

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4 years ago

Please Help me with this URGENT

timama [110]

Answer:

y = [-½]x + [-5]

Step-by-step explanation:

Equation describing how x and y are related can be written in slope-intercept form, y = mx + b.

m = slope = ∆y/∆x

Using two pairs of values from the table, (-2, -4) and (0, -5),

Slope (m) = (-5 - (-4))/(0 - (-2)) = -1/2

m = -½

b = y-intercept = the value of y when x is 0 = -5

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3 years ago

What does -4(3x-4)=44 What is x

eduard

Answer:

-7/3

Step-by-step explanation:

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3 years ago

A person gets on and off a bathroom scale four times. The four readings (in pounds) are 148, 151, 150, and 152. Each time after

Ganezh [65]

Answer:

See explanation below

Step-by-step explanation:

Since each time after the person gets off the scale, the reading is 2 lb the person's weight must be near the mean of

148-2, 151-2, 150-2, 152-2; that is to say, near the mean of 146, 149, 148, 150 = (146+149+148+150)/4 = 148.25

We could estimate the uncertainty as the standard error SE

$\bf SE=\frac{s}{\sqrt{n}}$

where

s = standard deviation of the sample

n = 4 sample size.

Computing s:

$\bf s=\sqrt{\frac{(146-148.25)^2+(149-148.25)^2+(148-148.25)^2+(150-148.25)^2}{4}}=1.479$

So, the uncertainty is 1.479/2 = 0.736

It is not possible to estimate the bias, since it is the difference between the true weight and the mean, but we do not know the true weight.

5 0

3 years ago

Given P(E)= 0.24 and P(FnE)= 0.17, find P(F| E). Round the answer to the nearest hundredth. A. 029 B. 0.40 C. 0.71 D. 1.41

romanna [79]

Given P(E) = 0.24 and P(F ∩ E) = 0.17

It says to find conditional probability of F given E has occurred.

We know the formula of conditional probability is given by :-

P(F ║ E) = $\frac{P(E\;and\; F)}{P(E)}$

P(F ║ E) = $\frac{0.17}{0.24}$ = 0.708333

P(F ║ E) = 0.71

Hence, option C i.e. 0.71 is the final answer.

7 0

3 years ago