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4 years ago

Equivalent expression to 40+4x

Mathematics

1 answer:

spayn [35]4 years ago

4 0

Answer:

Don't delete mistystar

Step-by-step explanation:

60-20-4x+8x

is equivalent:

60-20-4x+8x=40+4x

simplify

40+4x=40+4x

0=0

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What is 56,129,482 rounded

JulsSmile [24]

56,129,480 is the answer

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3 years ago

Two angles are supplementary. the measure of one angle is 4 more than 2 times the measure of teh other andgle. Write an equation

ch4aika [34]

Answer:

$y=58.67^{\circ}$

$x=121.33^{\circ}$

Step-by-step explanation:

We are given that two angles are supplementary .

We have to write an equation that can be used to find the measures.

Let x and y are supplementary

According to question

$x+y=180^{\circ}$ ( by definition of supplementary angles)

$x=2y+4$

Substitute the value then we get

$2y+4+y=180$

$3y=180-4$

$3y=176$

$y=\frac{176}{3}$

$y=58.67^{\circ}$

Substitute the value then, we get

$x+58.67=180$

$x=180-58.67$

$x=121.33^{\circ}$

3 0

4 years ago

Find P(3) when µ = 4<br><br>there wasn't any prior information.<br><br>It was added

blagie [28]

<h3>Answer: P(3) = 0.20</h3>

====================================================

Explanation:

The Poisson PDF value is given by the function

P(x) = ( e^(-mu)*mu^x )/(x!)

where the exclamation mark indicates a factorial

In this case, mu = 4, so we can update the equation into

P(x) = ( e^(-4)*4^x )/(x!)

Now plug in x = 3 to finish off the problem

P(x) = ( e^(-4)*4^x )/(x!)

P(3) = ( e^(-4)*4^3 )/(3!)

P(3) = 0.1953668148129

P(3) = 0.20

Note: The 'e' is a special constant which is approximately e = 2.718, similar to how pi = 3.14 is a constant used often.

6 0

3 years ago

If A=(-1,-3) and B=(-11,-8), what is the length of AB

tester [92]

The length of AB is 15

8 0

3 years ago

Mark ran 875 miles this year in the track club.Mark ran in 52 track meets and ran the same number of miles in each.How many mile

shepuryov [24]

Answer:

The number of miles Mark runs in each track be $16 \frac{43}{52}\ miles$

Step-by-step explanation:

Let us assume that the number of miles Mark run in each track meet be x.

As given

Mark ran 875 miles this year in the track club.

Mark ran in 52 track meets and ran the same number of miles in each.

Than the equation becomes

52 × x = 875

$x = \frac{875}{52}$

$x = 16 \frac{43}{52}\ miles$

Therefore the number of miles Mark runs in each track be $16 \frac{43}{52}\ miles$

7 0

3 years ago