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3 years ago

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Mark ran 875 miles this year in the track club.Mark ran in 52 track meets and ran the same number of miles in each.How many mile

s did Mark run in each track meet? Write the answer as a mixed number.

1 answer:

shepuryov [24]3 years ago

7 0

Answer:

The number of miles Mark runs in each track be $16 \frac{43}{52}\ miles$

Step-by-step explanation:

Let us assume that the number of miles Mark run in each track meet be x.

As given

Mark ran 875 miles this year in the track club.

Mark ran in 52 track meets and ran the same number of miles in each.

Than the equation becomes

52 × x = 875

$x = \frac{875}{52}$

$x = 16 \frac{43}{52}\ miles$

Therefore the number of miles Mark runs in each track be $16 \frac{43}{52}\ miles$

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However, we are working with samples that are considerably big. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

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The standard deviation of the binomial distribution is:

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Normal probability distribution

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What is the probability that tomorrow more than 35 domestic passengers will accidentally get caught with a gun at the airport?

This probability is 1 subtracted by the pvalue of Z when X = 35. So

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8 0

3 years ago