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3 years ago

15

HELPPP!!! help me for a brainliest!

1 answer:

Radda [10]3 years ago

8 0

<em>=</em><em>5</em><em>^</em><em>6</em><em>/</em><em>5</em><em>^</em><em>4</em>

<em>=</em><em>5</em><em>^</em><em>(</em><em>6</em><em>-</em><em>4</em><em>)</em>

<em>=</em><em>5</em><em>^</em><em>2</em><em> </em><em>ANSWER</em><em>.</em><em>.</em>

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Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago

HELP ASAP!! WILL MARK AS BRAINLIEST IF ANSWERED NOW!!!!

tiny-mole [99]

Answer: She should blend 98 lbs of high-quality beans.

She should blend 72 lbs of cheaper beans

Step-by-step explanation:

Let x represent the number of pounds of high quality beans that she should blend.

Let y represent the number of pounds of cheaper beans that she should blend.

She needs to prepare 170 lbs of blended coffee beans. This means that

x + y = 170

She plans to do this by blending together a high-quality bean costing $4.75 per pound and a cheaper bean at $2.00 per pound. The blend would sell for $3.59 per pound. This means that the total cost of the blend would be 3.59×170 = $610.3. This means that

4.75x + 2y = 610.3 - - - - - - - - - -1

Substituting x = 170 - y into equation 1, it becomes

4.75(170 - y) + 2y = 610.3

807.5 - 4.75y + 2y = 610.3

- 4.75y + 2y = 610.3 - 807.5

- 2.75y = - 197.2

y = - 197.2/-2.75 = 71.9

y = 72 pounds

x = 170 - y = 170 - 71.9

x = 98.1

x = 98 pounds

4 0

3 years ago

Diane is selling raffle tickets. For every 4 tickets, she charges $32.

madam [21]

Answer:

There's no table but

Step-by-step explanation:

4 tickets = $32

8 tickets = $64

Sorry if I didn't help:/.

3 0

3 years ago

A bag contains five red marbles, four blue marbles, and three yellow marbles. You randomly pick a marble. What is the probabilit

seraphim [82]

The ratio is 9/12 and you can write it as a proportion. so you multiply 9 by 100 then divide it by 12. answer is 75% chance

7 0

3 years ago

Given the equation 4x2 − 8x 20 = 0, what are the values of h and k when the equation is written in vertex form a(x − h)2 k = 0?

Westkost [7]

The vertex form of the given quadratic equation is

$4(x-1)^{2} + 16 =0$ .

According to the given question.

We have a quadratic equation

$4x^{2} -8x + 20 = 0$

Since, for the standard quadratic form is $ax^{2} +bx + c = y$ , the vertex form of a quadratic equation is $y = a(x -h)^{2} + k$ where (h, k) is the vertex.

And h and k can be calculated as

h = -b/2a and y = k

So, for the given equation $4x^{2} -8x + 20 =0$ the vertex (h, k) is given by

h = -(-8)/2(4) = 8/8 = 1 (X coordinate of vertex)

and,

$y =4x^{2} -8x+ 20$

substitute x = 1 in the above equation for the value of k

Y = 4(1)(1) - 8(1) + 20

⇒ Y = 4 - 8 + 20

⇒ Y = -4 + 20

⇒ Y = 16

so, k = 16 (Y coordinate of vertex)

Now, substitute the value of a, k and h in $y = a(x-h)^{2} + k$ .

⇒ $0 =4(x-1)^{2} + 16$

Therefore, the vertex form of the given quadratic equation is

$4(x-1)^{2} + 16 =0$ .

Find out more information about vertex form of a quadratic equation here:

brainly.com/question/12223454

#SPJ4

6 0

2 years ago