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almond37 [142]
3 years ago
15

What is 12.35 rounded to the nearest tenth

Mathematics
2 answers:
blsea [12.9K]3 years ago
4 0
12.35 rounded to the nearest tenth is 12.4. Since the number in the hundredths place is 5 and up, you round the number in the tenths place up.
fiasKO [112]3 years ago
3 0
12.35 rounded to the nearest tenth is 10.00 or just 10. The reason for this is the placement of the decimal point. Since the decimal is after the 1 and 2, then that means the 12 is a whole number. Since the 3 and 5 is before the decimal, they're only a fraction of a whole number.
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To prepare for a party, Abby poured 0.45 liter of juice into each of several cups. Altogether she poured 9 liters of juice into
saw5 [17]

Answer:

20 cups

Step-by-step explanation:

divide 9 by .45 and you get 20

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4 years ago
(9r²+5r-11) - (-2r²+9r-8)
Alex787 [66]

Answer:

11r²-4r-3

Step-by-step explanation:

soo,, now firstly change the signs of 2nd expression  

so,  

9r²+5r-11+2r²-9r+8

now  

we will combine the same terms like , see next step

9r²+2r²+5r-9r-11+8

11r²-4r-3

3 0
3 years ago
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What is the area of the triangle shown below? 13 13 10
Firdavs [7]

Answer: 60 units^2

Step-by-step explanation:

6 0
3 years ago
What is meant by "bias due to selective survival" in cross-sectional studies? Under what circumstances might there be no selecti
Rudik [331]

Answer:

What is meant by "bias due to selective survival" in cross-sectional studies?

First lets understand what is selective bias in cross-sectional studies. Basically its the bias that occurs when the random sample data for some analysis is selected in improperly. Such a selected sample is not able to represent the population that is to be analyzed. The reason is the improper randomization. So "bias due to selective survival" means that only the survival participants or survivors can be considered in this cross sectional studies. So if there is more probability of exposed cases to survive than unexposed cases or it could also be possible that unexposed cases have more probability to survive than exposed ones, so in either case the conclusion drawn from this cross sectional studies may differ from the proper cohort study. So the selective bias is introduced. Hence we can say that there is bias due to selective survival.

Step-by-step explanation:

Under what circumstances might there be no selective survival bias even if the selection probabilities are not all equal?

If the cross product of selection probabilities equals 1. Then there might be no selective survival bias even if the selection probabilities are not all equal. As we know that the cross product of odd ratio of selection probabilities is 1 means there is no relation between exposure and consequence or outcome and there is no bias in odd ratio.

Suppose that you could assess that the direction of possible selective survival bias in your study was towards the null. If your study data yielded a non-statistically significant odds ratio of 1.04, would it be correct to conclude that there was no exposure-disease association in your source population?

It would not be correct to conclude that there was no exposure-disease association in your source population because if the possible selective survival bias in the study was towards the null then this implies that the true odds ratio would be larger than 1.04. and therefore likely to be large and also differ statistically for the null value.

8 0
3 years ago
What is the first step to solve the following system of equations using substitution?
Akimi4 [234]

Answer:

Step 1: Solve one of the equations for one of the variables. Let's solve the first equation for x

Thus, option A) is true.

The solution to the system of equations be:

x = 4, y = 5

Step-by-step explanation:

It is important to remember that when we solve the system of equations, the first step we need to do is to solve one of the equations for one of the variables.

Given the system of equations

x - y = -1

2x - y = 3

Step 1: Solve one of the equations for one of the variables. Let's solve the first equation for x

x-y=-1

Add y to both sides

x-y+y=-1+y

x=-1+y

Thus, option A) is true.

<u>NOW LET US SOLVE THE REMAINING PORTION</u>

\mathrm{Subsititute\:}x=-1+y to solve for y

\begin{bmatrix}2\left(-1+y\right)-y=3\end{bmatrix}

-2+y=3

y=5

For x = -1 + y

substitute y = 5

x=-1+5

x=4

Thus, the solution to the system of equations be:

x = 4, y = 5

3 0
3 years ago
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