Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
Answer:
.
Step-by-step explanation:
We have been given that Mrs. Chen's students are making and decorating gift boxes for a nursing home. The boxes are 7 inches wide, 7 inches long, and 7 inches high. We are asked to find the amount of cardboard that is needed for each box.
We will use surface area of cuboid formula to solve our given problem.
, where,
l = Length,
w = Width,
h = Height




Therefore, Mrs Chen needs 84 square inches of cardboard.
Answer:
I'm pretty sure it would be base x height divided by 2 so 20×6÷2
Least to greatest: 0.7 0.9 0.73 0.81
743 u should do the divide by three trick