Expand log_1/2(3x^2/2) using the properties and rules for logarithms.
Please help.
2 answers:
Answer:
-0.58-6.64log(x)
Step-by-step explanation:
The given expression is

It can be rewritten as

Using the properties and rules for logarithms, we get
![[\because log_a(mn)=log_am+log_an]](https://tex.z-dn.net/?f=%5B%5Cbecause%20log_a%28mn%29%3Dlog_am%2Blog_an%5D)
![[\because log_a(a)=1,logx^n=nlogx]](https://tex.z-dn.net/?f=%5B%5Cbecause%20log_a%28a%29%3D1%2Clogx%5En%3Dnlogx%5D)
![[\because log_a(b)=\frac{logb}{loga}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20log_a%28b%29%3D%5Cfrac%7Blogb%7D%7Bloga%7D%5D)
![[\because log\frac{a}{b}=loga-logb]](https://tex.z-dn.net/?f=%5B%5Cbecause%20log%5Cfrac%7Ba%7D%7Bb%7D%3Dloga-logb%5D)
We know that,
log (1) = 0
log (2) = 0.301
log (3) = 0.477
Substitute these values in the



Therefore, the expanded form of given expression is -0.58-6.64log(x).
Answer:

Step-by-step explanation:
Data provided:

now,
we know the properties of log functions as:
1) log(AB) = log(A) + log(B)
2)
= log(A) - log(B)
3) log(xⁿ) = n × log(x)
thus,
=
- 
or
=
- 
or
using property 3
=
- 
also,

thus,
= ![\frac{\log(3)}{\log(\frac{1}{2})}+2\times[\frac{\log(x)}{\log(\frac{1}{2}}]-\frac{\log(2)}{\log(\frac{1}{2})}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Clog%283%29%7D%7B%5Clog%28%5Cfrac%7B1%7D%7B2%7D%29%7D%2B2%5Ctimes%5B%5Cfrac%7B%5Clog%28x%29%7D%7B%5Clog%28%5Cfrac%7B1%7D%7B2%7D%7D%5D-%5Cfrac%7B%5Clog%282%29%7D%7B%5Clog%28%5Cfrac%7B1%7D%7B2%7D%29%7D)
or
= 
or
= 
now,
log(1) = 0
log(2) = 0.3010
log(3) = 0.4771
thus,
= 
or
= 
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