1. Growth
2. Tumor
3. Body
Answer:
Explanation:
1. Over time more and more molecules of DCPIP would be decreased by electrons taken from plastoquinone (Pq). This statement is true in the sense that DCPIP is an artificial electronic acceptor which is decreased by taking electrons from plastoquinone.
2.) Water splitting by Photosystem II would occur at higher levels than if the drug were administered without DCPIP. This statement is true.
3.)Events in Photosystem I would occur just as they would in the absence of drug and DCPIP. This statement is false because the drug obstructs the electron transport from plastoquinone to cytochrome B. So the events are abnormal because no protein transfer is involved in this mechanism.
Answer:
The transfer of mature pollen grain from anther of the flower to the stigma of the same flower of the same [species is called self pollination.
Generally, the transfer of pollen grains by wind,animals,and water to stigmas is called pollination. It is a means of vegetative propagation which ensures reproduction.
Therefore during self pollination, the same genes are distributed from one generation to another. Thus genetic purity is ensured. It also ensured reproductive success. because there is little chance of the pollen grain getting lost in transit. It is also certain a particular plant would always breed true.
Additionally it prevent the process of transfer of genes in some transgenic crops( rice, maize) where through genetic engineering some genes are introduced in their genome.
The only negative effect is lack of genetic diversity. Therefore after a period of time the plants get weak and prone to diseases and infection. Because of poor resistant from lack of variation.
Explanation:
42% of rabbits in the population are heterozygous for the mutant Sp1 allele
Hardy-Weinberg equilibrium
- Assume that p is the frequency of the dominant allele
- p² is the frequency of the organisms with homozygous dominant genotype
- Assume that q is the frequency of the recessive allele
- q² is the frequency of the organisms with homozygous recessive genotype
- 2pq is the frequency of the organisms with heterozygous genotype
- p+q = 1
According to the question, 900 out of 10000 rabbits are homozygous recessive
- This implies that q² = 900/10000= 9/100= 0.09
- So, q = 0.3
- The frequency of the recessive allele is 0.3
- p = 1-q = 1-0.3= 0.7
For organisms with heterogenous genotype, their frequency is 2pq
2pq= 2 x 0.3 x 0.7 = 0.42
In terms of percentage, 0.42x 100% = 42%
Therefore, 42% of rabbits in the population are heterozygous for the mutant Sp1 allele.
Learn more about Hardy-Weinberg equilibrium here:
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