Answer:
Step-by-step explanation:
<u>Figure 1</u>
<u>Figure 2</u>
<u>Figure 3</u>
<u>Equation for nth term</u>
- (n + 1)^2 - 2 =
- n^2 + 2n + 1 - 2 =
- n^2 + 2n - 1
That would be the cube root of (x+5)^11.
If desired, this could be reduced to the cube root of (x+5)^9*(x+5)^2, which would be
(x+5)^3*(x+5)^(2/3)
Correct me if i am wrong, but wouldn't the inverse simply be
{(3,-5),(-2,-4),(-5,-8)}?
Answer:
(5/7)m + 2n + 3
Step-by-step explanation:
Rewrite 3/7m as (3/7)m for added clarity, also 2/7m as (2/7)m.
Adding (3/7)m and (2/7)m results in (5/7)m.
Next, combine -3 and 6, which yields 3.
I expected that there'd be only one term in m in both quantities. (3/7)m - 3 + 4n does have only one term, but (2/7)m - 2m + 6) seems to have two m terms. I will assume that you actually meant (2/7)m - 2n + 6).
Combining like terms, we get (5/7)m + 3 + 4n - 2n, or
(5/7)m + 2n + 3
