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3 years ago

How do I do question 9 b?

Mathematics

1 answer:

Lynna [10]3 years ago

3 0

You find the circumference of a full circle so 2πr =43.98
then divide by 4=10.995
so the answer is 10.995cm

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Write an equation for a parabola in which the set of all points in the plane are equidistant from the focus and line F(-6,0); x=

Bogdan [553]

Step-by-step explanation:

Since we have a vertical directrix, the equation of the parabola is

$(y - k) {}^{2} = 4p(x - h)$

Where p is the distance from the vertex to the directrix.

or the distance from the vertex to the focus.

Since we have a sideways parabola, let use the point for the directrix is (-6,0). So let find the midpoint of (-6,0) and (6,0). That would be our vertex.

$\frac{ - 6 + 6)}{2} = 0$

$\frac{0 + 0}{2} = 0$

So our vertex is (0,0).

So our equation become

${y}^{2} = 4px$

The distance from the focus and directrix is 6.

So p=6.

${y}^{2} = 24x$

So p is 6.

Since p is 6,

$\frac{ {y}^{2} }{24} = x$

3 0

2 years ago

3(2x+1)=7-2(x+5)<br> Can you please show me how to solve this step by step please

Talja [164]

3(2x+1) = 7-2(x+5)
6x+3 = 7-2x-10
-3 -3
6x = 7-2x-10-3
+2x +2x
8x = -6
---- -----
8 8
x = -3/4

8 0

3 years ago

Ámala caught 54 fishes, she released 5/6 how many she keep

matrenka [14]

9 fish (:
5/6 of 54 is 45, so you would need to subtract 45 from 54, which is 9.
I hope you find this useful, and, if so, please mark as brainliest :P
Good luck!

4 0

3 years ago

Read 2 more answers

A while back, either James borrowed $12 from his friend Rita or she borrowed $12 from him, but he can’t quite remember which. Ei

oksano4ka [1.4K]

The answer is x=42.8+- (plus or minus) 12

So he should either have $30.80 or $44.80 left

6 0

3 years ago

I need help with this math question

ICE Princess25 [194]

Answer:

B. 5

Step-by-step explanation:

Step 1: Rewrite the equation a bit

$\frac{7^\frac{3}{4}}{7^\frac{x}{8}}=\sqrt[8]{7}\\7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}$

Step 2: Place a logarithm base 7 on both sides

$7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}\\log_77^\frac{3}{4}^-^\frac{x}{8}=log_77^\frac{1}{8}\\(\frac{3}{4}-\frac{x}{8})log_77=\frac{1}{8}log_77\\(\frac{3}{4}-\frac{x}{8})1=\frac{1}{8}1\\\frac{3}{4}-\frac{x}{8}=\frac{1}{8}$

Step 3: Solve for x

$\frac{3}{4}-\frac{x}{8}=\frac{1}{8}\\\frac{6}{8}-\frac{x}{8}=\frac{1}{8}\\-\frac{x}{8}=-\frac{5}{8}\\\frac{x}{8}=\frac{5}{8}\\x=5$

Neat exponent question :)

7 0

2 years ago