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Oduvanchick [21]
3 years ago
14

Which of the following statements are true regarding functions? Check all that apply. A.The vertical line test may be used to de

termine whether a function is one-to-one. B. A sequence is a function whose domain is the set of real numbers. C. A function is a relation in which each value of the input variable is paired with exactly one value of the output variable. D. The horizontal line test may be used to determine whether a function is one-to-one.
Mathematics
2 answers:
Stolb23 [73]3 years ago
8 0

Answer:

A & D

Step-by-step explanation:

BigorU [14]3 years ago
6 0
The answer o this question would be: 
<span>A.The vertical line test may be used to determine whether a function is one-to-one
</span><span>D. The horizontal line test may be used to determine whether a function is one-to-one.

Vertical and horizontal line test can be used to find out whether the function, not one-to-one. The test is done by making a horizontal line (for horizontal line test) or vertical line( for vertical line test). If there are no 2 or more points of the graph that touch the line in both tests, then the function would be one-to-one</span>
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gizmo_the_mogwai [7]
If you are trying to solve for x, then 
4x+5<=13
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4x<=8
then divide both sides by 4 
x<=2
5 0
4 years ago
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Hi!
suter [353]

Answer:

1 median=60.3

2 missing number=38

Step-by-step explanation:

1 45+55+76+y+88+54/6

316+y/6=63.6

316+x381.6

x=381.6-316=65.6

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60-62+92+x/4=63

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3 years ago
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LOTS OF POINTS GIVING BRAINLIEST I NEED HELP PLEASEE
Sidana [21]

Answer:

Segment EF: y = -x + 8

Segment BC: y = -x + 2

Step-by-step explanation:

Given the two similar right triangles, ΔABC and ΔDEF, for which we must determine the slope-intercept form of the side of ΔDEF that is parallel to segment BC.

Upon observing the given diagram, we can infer the following corresponding sides:

\displaystyle\mathsf{\overline{BC}\:\: and\:\:\overline{EF}}

\displaystyle\mathsf{\overline{BA}\:\: and\:\:\overline{ED}}

\displaystyle\mathsf{\overline{AC}\:\: and\:\:\overline{DF}}

We must determine the slope of segment BC from ΔABC, which corresponds to segment EF from ΔDEF.

<h2>Slope of Segment BC:</h2>

In order to solve for the slope of segment BC, we can use the following slope formula:

\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}  }

Use the following coordinates from the given diagram:

Point B:  (x₁, y₁) =  (-2, 4)

Point C:  (x₂, y₂) = ( 1,  1 )

Substitute these values into the slope formula:

\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{1\:-\:4}{1\:-\:(-2)}\:=\:\frac{-3}{1\:+\:2}\:=\:\frac{-3}{3}\:=\:-1}

<h2>Slope of Segment EF:</h2>

Similar to how we determined the slope of segment BC, we will use the coordinates of points E and F from ΔDEF to find its slope:

Point E:  (x₁, y₁) =  (4, 4)

Point F:  (x₂, y₂) = (6, 2)

Substitute these values into the slope formula:

\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{2\:-\:4}{6\:-\:4}\:=\:\frac{-2}{2}\:=\:-1}

Our calculations show that segment BC and EF have the same slope of -1.  In geometry, we know that two nonvertical lines are <u>parallel</u> if and only if they have the same slope.  

Since segments BC and EF have the same slope, then it means that  \displaystyle\mathsf{\overline{BC}\:\: | |\:\:\overline{EF}}.

<h2>Slope-intercept form:</h2><h3><u>Segment BC:</u></h3>

The <u>y-intercept</u> is the point on the graph where it crosses the y-axis. Thus, it is the value of "y" when x = 0.

Using the slope of segment BC, m = -1, and the coordinates of point C, (1,  1), substitute these values into the <u>slope-intercept form</u> (y = mx + b) to solve for the y-intercept, <em>b. </em>

y = mx + b

1 = -1( 1 ) + b

1 = -1 + b

Add 1 to both sides to isolate b:

1 + 1 = -1 + 1 + b

2 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 2.

Therefore, the linear equation in <u>slope-intercept form of segment BC</u> is:

⇒  y = -x + 2.

<h3><u /></h3><h3><u>Segment EF:</u></h3>

Using the slope of segment EF, <em>m</em> = -1, and the coordinates of point E, (4, 4), substitute these values into the <u>slope-intercept form</u> to solve for the y-intercept, <em>b. </em>

y = mx + b

4 = -1( 4 ) + b

4 = -4 + b

Add 4 to both sides to isolate b:

4 + 4 = -4 + 4 + b

8 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 8.

Therefore, the linear equation in <u>slope-intercept form of segment EF</u> is:

⇒  y = -x + 8.

8 0
3 years ago
Help with this one please
ivann1987 [24]

with what? you need to explain whats going on in order to get the help you need!

4 0
4 years ago
What is the best estimate of the perimeter of the figure on the grid if each square has side lengths of 1 mm?
Wewaii [24]

Answer:

4mm

Step-by-step explanation:

you have to add both sides after substituting each of the 4 sides by 1mm

which gives you the total of 4

6 0
2 years ago
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