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DaniilM [7]
3 years ago
8

Find the sum and express it in simplest Form (3a^2+2a+8)+(5a^2-a)

Mathematics
1 answer:
AlladinOne [14]3 years ago
8 0

Answer:

8a^2+a+8

Step-by-step explanation:

(3a^2+2a+8)+(5a^2-a)= \\\\(3a^2+5a^2)+(2a-a)+8= \\\\8a^2+a+8

Hope this helps!

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5/3x+1/3x=26 2/3+7/3x<br>solve for X​
Marat540 [252]

Let's solve your equation step-by-step.

5 /3 x+  1 /3 x=  262 /3  + 7 /3  x

x=−262

Description:

The first step is to simplify the equation step by step and to simplify an equation you can first multiplying the factors and use the exponent rules to remove the parentheses. After that youneed to combine it a terms. Then you will get your answer.

Answer:  x=−262

Hope this helps.

7 0
3 years ago
Mariana adoçou um suco com 1/4 de xícara de açúcar. Ao experimentar percebeu que não estava doce como gostaria e acrescentou mai
icang [17]

Answer: B 1/4 doc. de açúcar.

6 0
3 years ago
Graphing required <br><br><br> Help me ASAP
marta [7]
In the original graph, R (0,3), S(3,3), T(4, -1) and Q(0, 1)
Reflecting it across y=-1, which is a horizontal line going through the point T, all the x coordinates stay the same,
the new confidantes are : R'(0, -5), S'(3, -5), T'(4, -1), Q(0', -3) (Notice; T stays where it is now, because it is right now the line y=-1)
Locate these new points, you have your graph. 
6 0
3 years ago
Clara made two investments. Investment A has an initial value of $500 and
nalin [4]

Answer:

The first year in which Clara will see that Investment B's value will exceed Investment A's value will be year 14.

Step-by-step explanation:

Since Clara made two investments, and Investment A has an initial value of $ 500 and increases by $ 45 every year, while Investment B has an initial value of $ 300 and increases by 10% every year, and Clara checks the value of her investments once to year, at the end of the year, to determine what is the first year in which Clara sees that Investment B's value has exceeded investment A's value, the following calculation must be performed:

500 + (45 x X) = A

300 x 1.1 ^ X = B

A = 500 + 45 x 5 = 500 + 225 = 725

B = 300 x 1.1 ^ 5 = 483.15

A = 500 + 45 x 10 = 950

B = 300 x 1.1 ^ 10 = 778.12

A = 500 + 45 x 15 = 1175

B = 300 x 1.1 ^ 15 = 1253.17

A = 500 + 45 x 14 = 1,130

B = 300 x 1.1 ^ 14 = 1,139.25

Therefore, the first year in which Clara will see that Investment B's value will exceed Investment A's value will be year 14.

3 0
3 years ago
Wow ffghttyryryryrytergttyrgtgyg
Elenna [48]

Answer: Wow ffghttyryryryrytergttyrgtgyg hghgtotadgo

Step-by-step explanation:

7 0
3 years ago
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