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DaniilM [7]
3 years ago
8

Find the sum and express it in simplest Form (3a^2+2a+8)+(5a^2-a)

Mathematics
1 answer:
AlladinOne [14]3 years ago
8 0

Answer:

8a^2+a+8

Step-by-step explanation:

(3a^2+2a+8)+(5a^2-a)= \\\\(3a^2+5a^2)+(2a-a)+8= \\\\8a^2+a+8

Hope this helps!

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Write an equation in the form y= mx + b to represent the graph.
mixas84 [53]
Y=x-2





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5 0
3 years ago
PLEASE HELP VENN DIAGRAM!
algol13

Answer:

Yes.

Step-by-step explanation:

Since there is an overlap, that does mean some people with brown hair do wear watches, but not all of them do. Hence it's independent.

4 0
2 years ago
Find f(x) + g(x) when f(x) = 2x^2 + x and g(x) = 3x + 2
Artyom0805 [142]

Answer:

2x^2 + 4x+2

Step-by-step explanation:

f(x) = 2x^2 + x and g(x) = 3x + 2

f(x) + g(x) =  2x^2 + x + 3x + 2

            Combine like terms

               = 2x^2 + 4x+2

8 0
3 years ago
Read 2 more answers
Find a particular solution to the nonhomogeneous differential equation y′′+4y=cos(2x)+sin(2x).
I am Lyosha [343]
Take the homogeneous part and find the roots to the characteristic equation:

y''+4y=0\implies r^2+4=0\implies r=\pm2i

This means the characteristic solution is y_c=C_1\cos2x+C_2\sin2x.

Since the characteristic solution already contains both functions on the RHS of the ODE, you could try finding a solution via the method of undetermined coefficients of the form y_p=ax\cos2x+bx\sin2x. Finding the second derivative involves quite a few applications of the product rule, so I'll resort to a different method via variation of parameters.

With y_1=\cos2x and y_2=\sin2x, you're looking for a particular solution of the form y_p=u_1y_1+u_2y_2. The functions u_i satisfy

u_1=\displaystyle-\int\frac{y_2(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\int\frac{y_1(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx

where W(y_1,y_2) is the Wronskian determinant of the two characteristic solutions.

W(\cos2x,\sin2x)=\begin{bmatrix}\cos2x&\sin2x\\-2\cos2x&2\sin2x\end{vmatrix}=2

So you have

u_1=\displaystyle-\frac12\int(\sin2x(\cos2x+\sin2x))\,\mathrm dx
u_1=-\dfrac x4+\dfrac18\cos^22x+\dfrac1{16}\sin4x

u_2=\displaystyle\frac12\int(\cos2x(\cos2x+\sin2x))\,\mathrm dx
u_2=\dfrac x4-\dfrac18\cos^22x+\dfrac1{16}\sin4x

So you end up with a solution

u_1y_1+u_2y_2=\dfrac18\cos2x-\dfrac14x\cos2x+\dfrac14x\sin2x

but since \cos2x is already accounted for in the characteristic solution, the particular solution is then

y_p=-\dfrac14x\cos2x+\dfrac14x\sin2x

so that the general solution is

y=C_1\cos2x+C_2\sin2x-\dfrac14x\cos2x+\dfrac14x\sin2x
7 0
3 years ago
HELP ASAP ASAP ASAP ASAP ASAP ASAP
pishuonlain [190]

Answer:

x = 35 feet.

Step-by-step explanation:

Given that,

The height of the person is 5 feet.

The height of the flag and the eye is (x-5) feet.

We can calculate using trigonometry.

\tan\theta=\dfrac{(x-5)}{30}\\\\\tan(45)=\dfrac{(x-5)}{30}\\\\(x-5)=30\\\\x=30+5\\\\x=35\ ft

So, the value of x is equal to 35 feet. The correct option is (c).

5 0
3 years ago
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