Answer:
1)
Perimeter=24 inches
Area= around 43.46 inches
Step-by-step explanation:
1) Perimeter = 3in * number of sides
Perimeter = 3*8 = 24
Area= 2(1+ square root of 2) length of one side squared
=42.46
2)
Perimeter = 24
Area= 43.46 inches squared- 3inches
3)
Perimeter = 24
Area= 43.46- triangle area
triangle area = height x base /2
Height = 3, we can compare it.
Base = 3
Triangle = 9/2
Area = 43.46- 4.5
Area =38.96
Can't see 4 and 5 for some reason
6)
Perimeter = 30
Area = 61.94
Sorry if its incorrect, I am just 4th grade :(
Answer: 14:4 , 21:6 , 28:8 , 35:10
Step-by-step explanation:
The perpendicular bisector theorem gives the statements that ensures
that
and
are perpendicular.
The two statements if true that guarantee
is perpendicular to line
are;
Reasons:
The given diagram is the construction of the line
perpendicular to line
.
Required:
The two statements that guarantee that
is perpendicular to line
.
Solution:
From the point <em>C</em> arcs <em>E</em> and <em>D</em> are drawn to cross line
, therefore;
arcs drawn from the same radius.
is perpendicular to line
, given.
Therefore;
by perpendicular bisector theorem.
Learn more about the perpendicular bisector theorem here:
brainly.com/question/11357763
Well, to find the slop regardless, you do (Y2 - Y1) Divided by (X2 - X1). It is the same thing when finding the slope of any line.
Ex: (4,5) and (8,6). What is the slope? (6 - 5) / (8 - 4) = 1/4 <--- Slope
Please leave a thanks because you are welcome. Hope this helps :)
Answer:
First page
a: 0.864
b: x = 7, -8.75
Second page:
Domain: (3, ∞)
Range: (-∞, ∞)
Asymptote: x = 3
Third page: About 464 visitors
Step-by-step explanation:
See first attached photo for page 1 work
Second page: A log argument must be positive (the number in the log x place), so and number for x greater than 3 will satisfy this requirement.
x - 3 > 0, so x > 3
The range of a log x fucntion is (-∞, ∞),
Since x ≠ 3, there is a vertical asymptote at x = 3, the graph will not cross the line x = 3
*See second attached photo for the graph
Third page: Take the visitors of one year, and divide it by the visitors of the previous year to determine the % growth.
EX: from 2003 to 2004 the number of visitors grew from 310 to 322, a % change of
322/310 = 1.07, or 7%
Do this will all the years and you will see that each year there was about a 7% growth.
So in year 2009, there will be 434(1.07) = 464.38 visitors, or about 464 visitors