Answer:
2 vertical asymptotes occurring at x = 5 and x = -1
Step-by-step explanation:
given

recall that asymptotic occur at the locations that will make the equation undefined. In this case, the asymptote will occur at x-locations which will cause the denominator to become zero (and hence undefined)
Equating the denominator to zero,
(x-5)(x+1) = 0
(x-5) =0
x = 5 (first asymptote)
or (x+1) = 0
x = -1 (2nd asymptote)
Answer:
-3/5
Step-by-step explanation:
Pythagorean formula :
x^2 + y^2 = r^2
(-8)^2 + (-6)^2 = r^2
64 + 36 = 100
r^2 = 100
r= 10
sin is the y coordinate over the radius :
-6/10
-3/5
(25-y) ^2-y^2=25
y=12
x=25-12
x=13
(13,12)
Both integers have negative values
Explanation
Let
x and y represents the number
so, the options are

a) Both integers have negative values Both integers

b) Both integers have positive values

c)One integer has a positive value, and one integer has a negative value

d)The values of the two integers are opposites
as the point C , the sign depends on the bigger number
for example

so, the answer is Both integers have negative values
I hope this helps you